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3 years ago

(x+5)(x+3) Polynomial in standard form

Mathematics

1 answer:

Xelga [282]3 years ago

8 0

Answer:

Roots of the equation (x+3)(x+5)=0:

−3, multiplicity 1.

−5, multiplicity 1.

Step-by-step explanation:

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WILL GIVE BRAINLIEST.

Elena L [17]

Answer:

$\tan(\theta) =$ undefined

Step-by-step explanation:

Given

$\sin(\theta) = -1$

Required

Determine $\tan(\theta)$

We know that:

$\sin^2(\theta) + \cos^2(\theta) = 1$

This gives:

$(-1)^2 + \cos^2(\theta) = 1$

$1 + \cos^2(\theta) = 1$

Collect like terms

$\cos^2(\theta) = 1 -1$

$\cos^2(\theta) = 0$

Take square roots

$\cos(\theta) = \sqrt 0$

$\cos(\theta) = 0$

By tan identity

$\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}$

$\tan(\theta) = \frac{-1}{0}$

$\tan(\theta) =$ undefined

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3 years ago

The value of 60 is between which pair of consecutive numbers

finlep [7]

The answer would be
<span>59 and 60.</span>

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3 years ago

The diameter of a circle has endpoints whosever coordinates are R(-2,2) and S(4,2). find the center of the circle

lisov135 [29]

Hello!

As you can see this line is horizontal. It is 6 units long. Therefore the center is three units in. Therefore the center of this circle is at (1,2).

I hope this helps!

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3 years ago

James wants to go to the Texans football game. A ticket costs $79.50 plus tax. The tax rate is 6%. What is the total purchase pr

JulsSmile [24]

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Which equation can be solved to find one of the missing side lengths in the triangle?aB60512 unitsАCOS(60°) =22 믕cos(60°) = 12Su

Mekhanik [1.2K]

In a right rectangle, we have:

$\sin \alpha=\frac{opposite}{hypotenuse}$ $\cos \alpha=\frac{\text{adjacent}}{hypotenuse}$

For your exercice, hypotenuse=12

The exercise also inform the angle 60°, then:

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1 year ago

(x+5)(x+3) Polynomial in standard form​

(x+5)(x+3) Polynomial in standard form