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2 years ago

Y = 4x - 3y= 2x + 13

Mathematics

1 answer:

Serggg [28]2 years ago

7 0

Answer:

x = 9, y = 29 or (8,29)

Step-by-step explanation:

Set the equations equal to each other because they both equal y:

4x - 3 = 2x + 13

Combine like terms:

2x = 16

Divide by 2:

x = 8

Plug 8 into the x for both equations and see if the y is the same:

y = 4(8) - 3 = 32 - 3 = 29

y = 2(8) + 13 = 16 + 13 = 29

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If 890 was added to the data 42,43,44,46,81 it will be considered what because it is much high value than the other data?

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An outlier, it's when a number is much greater or lower than all the rest of the numbers.

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2 years ago

18 questions answered correctly on a test. that is 75% of the total number of questions. How many questions were on the test?

adelina 88 [10]

Answer:

24 = questions on test

Step-by-step explanation:

Questions answered correctly = questions on test * percent answered correctly

We know that she answered 18 correctly and that 75% were answered correctly

Substitute this information into the equation

18 = questions on test *.75

Divide by .75 on each side

18/.75 = questions on test *.75/.75

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2 years ago

(2-2) slope intercept form

____ [38]

Answer:

y=mx+b

Step-by-step explanation:

m=slope B= y intercept

(2-2) y=(mx+b)

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3 years ago

Find exact values for sin θ, cos θ and tan θ if csc θ = 3/2 and cos θ < 0.

kumpel [21]

Answer:

Part 1) $sin(\theta)=\frac{2}{3}$

Par 2) $cos(\theta)=-\frac{\sqrt{5}}{3}$

Part 3) $tan(\theta)=-\frac{2\sqrt{5}}{5}$

Step-by-step explanation:

step 1

Find the $sin(\theta)$

we have

$csc(\theta)=\frac{3}{2}$

Remember that

$csc(\theta)=\frac{1}{sin(\theta)}$

therefore

$sin(\theta)=\frac{2}{3}$

step 2

Find the $cos(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

$sin(\theta)=\frac{2}{3}$

substitute

$(\frac{2}{3})^{2} +cos^{2}(\theta)=1$

$\frac{4}{9} +cos^{2}(\theta)=1$

$cos^{2}(\theta)=1-\frac{4}{9}$

$cos^{2}(\theta)=\frac{5}{9}$

square root both sides

$cos(\theta)=\pm\frac{\sqrt{5}}{3}$

we have that

$cos(\theta) < 0$ ---> given problem

$cos(\theta)=-\frac{\sqrt{5}}{3}$

step 3

Find the $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=\frac{2}{3}$

$cos(\theta)=-\frac{\sqrt{5}}{3}$

substitute

$tan(\theta)=\frac{2}{3}:-\frac{\sqrt{5}}{3}=-\frac{2}{\sqrt{5}}$

Simplify

$tan(\theta)=-\frac{2\sqrt{5}}{5}$

6 0

2 years ago

Can someone help me asap!<br><br>

lilavasa [31]

Answer:

B negative

Step-by-step explanation:

use real numbers?

n is +9

m is -11

m/n * (-m*n^2)

-11/9 * (11*81)

-11/1 * (11*9)

-11 * 99

-1089

6 0

2 years ago

Y = 4x - 3y= 2x + 13​

Y = 4x - 3y= 2x + 13