2 years ago

To the girl who got it right is the one in the comments :D

Mathematics

1 answer:

Mama L [17]2 years ago

3 0

Dang that’s nice free points thank you

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The value of a certain car decreases by 16% each year. What is the 1⁄2-life of the car?

svet-max [94.6K]

Answer:

The half life of the car is 3.98 years.

Step-by-step explanation:

The value of the car after t years is given by the following equation:

$V(t) = V(0)(1-r)^{t}$

In which V(0) is the initial value and r is the constant decay rate, as a decimal.

The value of a certain car decreases by 16% each year.

This means that $r = 0.16$

$V(t) = V(0)(1-r)^{t}$

$V(t) = V(0)(1-0.16)^{t}$

$V(t) = V(0)(0.84)^{t}$

What is the 1⁄2-life of the car?

This is t for which V(t) = 0.5V(0). So

$V(t) = V(0)(0.84)^{t}$

$0.5V(0) = V(0)(0.84)^{t}$

$(0.84)^{t} = 0.5$

$\log{(0.84)^{t}} = \log{0.5}$

$t\log{0.84} = \log{0.5}$

$t = \frac{\log{0.5}}{\log{0.84}}$

$t = 3.98$

The half life of the car is 3.98 years.

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3 years ago

The Millers plan on retiring soon. When they were first married they purchased 1,000 shares in a mutual fund that was at that ti

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Answer: 6.8%

Step-by-step explanation:

We need to find both percentage so we can determine the increase.

Finding percentage of $10 return: 1% return

Finding percentage of $78 return: 7.8% return

To find the percent increase we do 7.8%-1.0% = 6.8%

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pav-90 [236]

Answer:

I believe it would be 18.568 or round up to 18

Step-by-step explanation:

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I don’t know honestly

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Alex73 [517]

Hello!

You can expand the 4

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the answer is 4x + 8

Hope this helps!

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