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AleksandrR [38]
3 years ago
5

Question: x/3 ≤ -6 answers: A) x ≤ -2 B) x ≥ -2 C) x ≤ -12 D) x ≤ -18 please help !!

Mathematics
2 answers:
xxMikexx [17]3 years ago
8 0
D Is the correct answer from what I can see
Alexandra [31]3 years ago
7 0
I think the answer is D
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8x1 = 8
Varvara68 [4.7K]
The correct answer is B
8 0
2 years ago
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I need help with the questions
riadik2000 [5.3K]

Answer:

Step-by-step explanation:

Hello

please find attached the graph

you can notice that x^2-6x+9 = (x-3)^2

(a) from the graph we can say that there is no maximum and one minimum in x = 3

and then f(3) = 0 so o is the minimum of f

(b) vertex is (3,0)

(c) x = 3 is an axis of symmetry

(d) as x^2-6x+9 = (x-3)^2 the root is 3

(e) y=9 for x = 0 so the y-intercept is 9

do not hesitate if you need further explanation

if you like my answer, tag it as the brainliest :-)

8 0
2 years ago
Evaluate 8P4 how can I evaluate this problem
Leno4ka [110]
NPr = n! / (n-r)!

8P4 = 8! / (8-4)!

= 8! / 4!

= 1,680
5 0
3 years ago
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Please helpp will mark brainlyist
chubhunter [2.5K]
I’m pretty sure it’s (3.63)


3.631923997916374
6 0
3 years ago
Show that cos2x=cosx
PSYCHO15rus [73]

cos (2x) = cos x

2 cos^2 x -1 = cos x   using the double angle formula

2 cos ^2 x -cos x -1 =0

factor

(2 cos x+1) ( cos x -1) = 0

using the zero product property

2 cos x+1 =0    cos x -1 =0

2 cos x = -1       cos x =1

cos x = -1/2       cos x=1

taking the arccos of each side

arccos cos x = arccos (-1/2)         arccos cos x = arccos 1

x = 120 degrees   x=-120   degrees           x=0

remember you get 2 values ( 2nd and 3rd quadrant)

these are the principal values

now we need to add 360

x = 120+ 360n      x=-120+ 360n      x = 0 + 360n  where n is an integer


3 0
3 years ago
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