1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SVETLANKA909090 [29]
3 years ago
14

Last week, the members of a weight loss support group collectively weighed 1,580 pounds. They just weighed in again and are now

5% lighter. What is the group's current weight?
Mathematics
1 answer:
rosijanka [135]3 years ago
3 0

Answer: 1,501

Step-by-step explanation:

100% = 1,580

100% - 5% lost

95%

1580 x .95 = 1501

You might be interested in
Decide whether the table shows a proportional relationship between x and y.
Serga [27]

Answer:

Yes

Step-by-step explanation:

I think it is proportional relationship. I hope my answer help you.

5 0
3 years ago
Have another question! will give brainliest again
stepan [7]

Answer:

-64

Step-by-step explanation:

If I represent the worker's position relative to the surface of the earth then

if we let Δy = the change of position.

Δy = 0 -64 \\ Δy = -64

5 0
3 years ago
Help due 11:59!!!!!!!​
blagie [28]

Answer:

4,6 hope this helps you

5 0
2 years ago
Helpppppp is required
seraphim [82]

Answer:

im pretty sure its C. X=4 but im not positive.

7 0
3 years ago
The weight of people in a small town in Missouri is known to be normally distributed with a mean of 186 pounds and a standard de
OleMash [197]

Answer:

the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

Step-by-step explanation:

The summary of the given statistical data set are:

Sample Mean = 186

Standard deviation = 29

Maximum capacity 3,417 pounds or 17 persons.

sample size = 17

population mean =3417

The objective is to determine the probability  that a random sample of 17 persons will exceed the weight limit of 3,417 pounds

In order to do that;

Let assume X to be the random variable that follows the normal distribution;

where;

Mean \mu = 186 × 17 = 3162

Standard deviation = 29* \sqrt{17}

Standard deviation = 119.57

P(X>3417) = P(\dfrac{X - \mu}{\sigma}>\dfrac{X - \mu}{\sigma})

P(X>3417) = P(\dfrac{3417 - \mu}{\sigma}>\dfrac{3417 - 3162}{119.57})

P(X>3417) = P(Z>\dfrac{255}{119.57})

P(X>3417) = P(Z>2.133)

P(X>3417) =1- 0.9834

P(X>3417) =0.0166

Therefore; the probability that a random sample of 17 persons will exceed the weight limit of 3,417 pounds is 0.0166

5 0
3 years ago
Other questions:
  • Which of the sequences is an arithmetic sequence?
    11·2 answers
  • What sequence starts with 1 and has a common difference of 2
    12·1 answer
  • How do you divide 20 into 171
    5·1 answer
  • Pleas help me Solve- 8/0.5 ​
    6·2 answers
  • What values of x make the (x-2)(x+7) expression negative
    8·1 answer
  • I'LL LOVE YOU FOREVER PLZ<br> btw ik its C but how do i get that answer?
    14·1 answer
  • Help ASAP
    7·1 answer
  • HELP PLS ANSWER IT FR FR
    6·2 answers
  • How many days in 4 years?<br><br> Answer: 1461
    8·2 answers
  • Beau wants to pick two people at random in his class to
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!