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I am Lyosha [343]
3 years ago
11

Mark tosses a coin 25 times. What is the probability that it lands on heads exactly seven times?

Mathematics
1 answer:
mezya [45]3 years ago
6 0

Answer:

1.43%

Step-by-step explanation:

we have that we can solve it by means of binomial, in this case m = 25. Also the probability of head is 50%. we need to know when it falls 7 times, therefore x = 7

the formula is:

P (x) = mCx * p ^ x * q ^ (m-x)

we know that p is 0.5 therefore q is equal to 0.5, replacing:

P (7) = 25C7 * 0.5 ^ 7 * 0.5 ^ (25-7)

P (7) = 25! / (7! * (25-7)!) * 0.5 ^ 7 * 0.5 ^ (25-7)

P = 0.0143

that is, the probability is 1.43%

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Match the values associated with this data set to their correct descriptions. {6, 47, 49, 15, 43, 41, 7, 36}
Brums [2.3K]

1st quartile: 11

median: 38.50000

3rd quartile: 45

<h3>According to the given information:</h3>
  • Order these numbers in increasing order: 6, 7, 15, 36, 41, 43, 47, 49
  • There is a 38.5 median (it is the mean of 36 and 41 - the pair of middle entries).
  • 6,7,15,36, or the left-most half of the data, make up the sample.
  • The median of the lower half is 11, which is the first quartile (it is the mean of 7 and 15 - the pair of middle entries).
  • 41, 43, 47, and 49, which are the data points in the upper half, are to the right of the median.
  • The median of the upper half is 45 in the third quartile (it is the mean of 43 and 47 - the pair of middle entries).
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Measure descriptive statistics

1st quartile: 11

median: 38.50000

3rd quartile: 45

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I understand that the question you are looking for is :

2 Drag the tiles to the boxes to form correct pairs. Match the values associated with this data set to their correct descriptions.  {6, 47, 49, 15, 43, 41, 7, 36} first quartile 38.5  median 11  third quartile 10.5 the difference of the largest value and the median 45

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2 years ago
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astraxan [27]

Answer:

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If you want, we can simplify that down further to:


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