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Xelga [282]
2 years ago
14

Round 61.98 to two significant figures

Mathematics
2 answers:
mixer [17]2 years ago
7 0
The answer is 62 because 9 is bigger than 5 so is possible to give 1 a partner so it will be 62
I think this well help
Nikolay [14]2 years ago
3 0
The answer is 62.00.
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Which expression is equivalent to x-5/3<br> ?
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Answer:

(A)

Step-by-step explanation:

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Solve the following equation for x.<br> 7x-3y=-13
MArishka [77]

Answer:

x = 3/7y - 13/7

Step-by-step explanation:

7x-3y=-13

  +3y   +3y        Add 3y to both sides

7x = 3y - 13       Divide both sides by 7

x = 3/7y - 13/7

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3 years ago
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A scuba diver descends in the water at a rate of 20 1/2 feet per minute for 2.8 minutes. He immediately changes course when he s
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Answer:

  • 7.4 feet below sea level

Step-by-step explanation:

Assumed the starting point is the sea level 0.

<u>After 2.8 min the diver is at position:</u>

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  • 20.5 * 2.8 =
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<u>The position change after next 2 minutes:</u>

  • 25*2 = 50 feet

<u>The position of the diver after 4.8 min:</u>

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2 years ago
Solve the system of the following equations:
schepotkina [342]
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Find equation of a line through 5 -3 that is parallel to y=1/2x+3
xxTIMURxx [149]

Answer:

The equation of a line through (5 -3) that is parallel to y = 1/2 x+3 is

y = - 2 x  + 7

Step-by-step explanation:

Let us assume the slope of the line whose equation we need to find is m 1.

The line parallel to the needed line  is:   y=1/2x+3

Comparing it with the general form: y = m x + C

we get m 2 = 1/2

Now, as Line 1 is Perpendicular to Line 2.

⇒ m 1 x m 2  = -1

⇒ m 1 x ( 1/2)  = -1

⇒ m 1  = - 2

Also, the point son the line 1 is given as: (x,y)  = (5,-3)

Put the value of point and Slope in y = m x + C to find the value of Y- INTERCEPT.

we get: -3 = (-2) (5) +  C

or, C = -3 + 10 = 7

⇒ C = 7

The general line equation is given as:  y = m x + C

Substituting  the values of C and m, we get:

y = - 2 x  + 7

Hence, the equation of a line through 5 -3 that is parallel to y = 1/2 x+3 is

y = - 2 x  + 7

8 0
3 years ago
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