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Tatiana [17]
3 years ago
14

The electric potential (voltage) at a specific location is equal to the potential energy per unit charge a charged object would

have if it were at that location. If the zero point of the voltage is at infinity, the numerical value of the voltage is equal to the numerical value of work done to bring in a unit charge from infinity to that location.
Select Show numbers and grid in the green menu, and drag one positive charge to the middle of the screen, right on top of two intersecting bold grid lines
What is the voltage 3 m away from the charge?
a. 3 V
b. 1 V
c. 9 V
Physics
1 answer:
Kruka [31]3 years ago
8 0

Answer:

The correct answer will be "4.5 V".

Explanation:

Potential electric due to change,

⇒  V=\frac{KQ}{r}

⇒  V \alpha \frac{1}{r}

As we know,

V₁ = 9

r₁ = 1

r₂ = 2

Now,

⇒  V_{1}r_{1}=V_{2}r_{2}

⇒  V_{2}=\frac{V_{1}r_{1}}{r_{2}}

On putting the estimated values, we get

⇒  V_{2}=\frac{9\times 1}{2}

⇒  V_{2}=\frac{9}{2}

⇒  V_{2}=4.5 \ V

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If the ball is stationary just before it is hit and goes 5.40 m high, what impulse did she impart to it?
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Energy is conserved. If the ball reaches a height of 5.50 m, it has gained a certain amount of gravitational potential energy. That energy had to come from somewhere. From this fact, you can deduce the speed of the ball at the end of the impact with the racket.

<h3>What is gravitational potential energy?</h3>

Gravitational energy or gravitational potential energy is the potential energy a huge item has corresponding to one more monstrous article because of gravity. It is the potential energy related with the gravitational field, which is delivered (changed over into active energy) when the articles fall towards one another. Gravitational potential energy increments when two articles are brought further apart. It is the potential energy related with the gravitational field, which is delivered (changed over into dynamic energy) when the items fall towards one another. Gravitational potential energy increments when two items are brought further separated.

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3 0
1 year ago
A) A wire made from iron with a cross-section of diameter 0.800 mm carries a current of 14.0 A. Calculate the "areal current den
Veseljchak [2.6K]

Answer:

A) ρ=1.74x10^{26}

B) μ=1.68x10^{29}\frac{electron}{m^3}

C) v=1.03x10^{-3}\frac{m}{s}

D)e=8.99x10^-9

Explanation:

A)

The magnetic field can be find knowing the current is the charge per second

β= \frac{14eC*s}{1.6x10^{-19}C}\\

β= 8.75x10^{19}e*s

Electron density

ρ=\frac{8.75x10^{19}}{\pi*0.400x10^{-3}m} = 1.74x10^{26}

B)

μ= \frac{7.86}{56.2}\frac{g}{cm^3} \frac{mol}{g}*6.022x10^{23}\frac{molecules}{mol} *2 \frac{electron}{molecule}

μ=1.68x10^{23} \frac{electron}{cm^3}= 1.68x10^{29} \frac{electron}{m^3}

C)

The drift speed using last information found

v= \frac{J}{n*q} \\v= \frac{14A}{\pi*((0.40x10^-3)^2)*1.68x10^29*1.60x10^-19)} = 1.03x10^-3(\frac{m}{s} )

D)

To compared the random thermal motion and the current's drift speed

e=\frac{1.03x10^-3}{1.15x10^5} = 8.99x10^-9

8 0
3 years ago
How many electrons can the first shell hold
Naily [24]
First shell hold up to 2 electrons.
8 0
4 years ago
A charged particle isinjected into a uniform magnetic field such that its velocity vector is perpendicular to themagnetic field
Bumek [7]

Answer:

D) follows a circular path

Explanation:

This is because the magnetic force F on the charge, q due to the magnetic field B with velocity vector v perpendicular to it, equals the centripetal force acting on the charge.

So, F = Bqv = mv²/r.

So it follows a circular path.

4 0
4 years ago
Read 2 more answers
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