Thermometer for the second part of question
Well formation of metallic bond depends on free electrons.smaal sized atoms hold their electrons more firmly as compared to large size atoms ,this z due to distance of outer shell electrons by nucleus..in this way no of free electrons affect strength of metallic bond..smaal sized atoms release less free electrons..
Answer:
2a.
a=1.13ms^-2
2b.
S=277m
2c.
V=27.7ms-¹
Explanation:
Initial Velocity (U)=22m/s¹
Final Velocity (V)=43m/s²
Time(t) =18.6s
a. a=V-U/t
a=43-22/18.6
a=1.129
a=1.13m/s²
2b.
S=ut+1/2 at²
s=22(10)+1/2×1.13(10)²
s= 220+0.57(10)²
s= 220+0.57(100)
s= 220+57
s=277m
2c.
V=U+AT
V=22+1.13(5)
V=22+5.65
V=22+5.7
V=27.7m/s¹
Answer:
(1) 42.94 m
(2) 
Explanation:
Let us first draw a figure, for the given question as below:
In the figure, we assume that the person starts walking from point A to travel 11 m exactly
south of west to point B and from there, it walks 21 m exactly
west of north to reach point C.
Let us first write the two displacements in the vector form:

Now, the vector sum of both these vectors will give us displacement vector from point A to point C.

Part (1):
the magnitude of the shortest displacement from the starting point A to point the final position C is given by:

Part (2):
As the vector AC is coordinates lie in the third quadrant of the cartesian vector plane whose angle with the west will be positive in the north direction.
The angle of the shortest line connecting the starting point and the final position measured north of west is given by:

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