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andrew11 [14]
3 years ago
13

How many hydrogen atom are present in 1.53 g of water

Chemistry
1 answer:
svp [43]3 years ago
3 0

Answer:

=1.02x10^{23} atoms\ H

Explanation:

Hello,

In this case, for water, whose molar mass is 18 g/mol, we can find two moles of hydrogen in one mole of water, therefore, for us compute the atoms, we should also use the Avogadro's number as shown below:

=1.53gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O} *\frac{6.022x10^{23}atoms\ H}{1molH} \\\\=1.02x10^{23} atoms\ H

Regards.

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Compute the freezing point of this solution:
likoan [24]

Answer:

Freezing point = 1.25

Explanation:

If  we increase the concentration of the solution, the concentration of H+ does not change.

Convert 2.5% in to decimal

2.5%  = 2.5 ÷100

        = 0.025

The freezing point = 0.025 × 50

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8 0
3 years ago
A molecule has the empirical formula C4H6O. If its molecular weight is determined to be about 212 g/mol, what is the most likely
krok68 [10]

Answer:

The molecular formula is C12H18O3

Explanation:

Step 1: Data given

The empirical formula is C4H6O

Molecular weight is 212 g/mol

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atomic mass of O = 16 g/mol

Step 2: Calculate the molar mass of the empirical formula

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Step 3: Calculate the molecular formula

We have to multiply the empirical formula by n

n = the molecular weight of the empirical formula / the molecular weight of the molecular formula

n = 70 /212 ≈ 3

We have to multiply the empirical formula by 3

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The molecular formula is C12H18O3

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<u>Answer:</u>

2.0158 grams

<u>Explantion:</u>

We are to find the mass of the hydrogen atoms in 1 mole of water.

We know that the formula of water is: H_2O

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As there are 2 atoms of hydrogen in water so 2 \times 1.00794 = 2.0158 grams is the answer

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3 years ago
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