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andrew11 [14]
3 years ago
13

How many hydrogen atom are present in 1.53 g of water

Chemistry
1 answer:
svp [43]3 years ago
3 0

Answer:

=1.02x10^{23} atoms\ H

Explanation:

Hello,

In this case, for water, whose molar mass is 18 g/mol, we can find two moles of hydrogen in one mole of water, therefore, for us compute the atoms, we should also use the Avogadro's number as shown below:

=1.53gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O} *\frac{6.022x10^{23}atoms\ H}{1molH} \\\\=1.02x10^{23} atoms\ H

Regards.

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