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Gemiola [76]
3 years ago
10

Please help I will mark Brainly

Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
3 0
The answer is b) 6. An element in group 6A has 6 valence electrons. 2 valence electrons are in s orbital and 4 valence electrons are in p orbital.
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What is the oxidation state of an individual nitrogen atom in nh4oh ? express the oxidation state numerically (e.g., +1)?
Nonamiya [84]
In NH4OH, the compounds that make it up are NH4+ and OH-
Therefore N exists in the ammonium form.
In the ammonium ion 4H atoms are connected to N. 
 N is more electronegative than H, therefore when H bonds to N, H is the more positive atom therefore each H has a charge of +1, since there are 4 H atoms the charge contributed by the 4H atoms are +1 * 4 = +4
the overall charge of NH4 is +1
Charge of N (+) +4 =  +1
Charge of N = +1 - 4
Therefore oxidation state of N in NH4 is  = -3
6 0
3 years ago
What is the molar mass of CHC13?
suter [353]

Answer:119.38 g/mol

Explanation:

Add the Molar mass of each element to get the final answer. Use the Periodic table to find the molar mass. Molar mass is located under neath the elements.

7 0
3 years ago
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Which of four fossils would be the most useful as a reference to determine the age of newly discovered fossils?why?
weqwewe [10]

Answer:

(A) fossil is the most useful.

It serves as an index fossil. The seashell is a great index fossil because it only appears in the sandstone layer in multiple locations in the same layer of time.

Explanation:

8 0
2 years ago
How much heat energy is needed to raise the temperature of 59.7g of cadmium from 25°C to 100°C? The specific heat of cadmium is
labwork [276]
     Using the Fundamental Equation of Calorimetry, we have:

Q=mc\Delta T \\ Q=59.7.0.231.(100-25) \\ \boxed {Q=1034.3025J}      

If you notice any mistake with my english, please know me, because I am not native.
7 0
3 years ago
The rate constant for the second-order reaction: 2NOBr(g) → 2NO(g) + Br2(g) is 0.80/(M · s) at 10°C. Starting with a concentrati
a_sh-v [17]

Answer : The concentration of NOBr after 95 s is, 0.013 M

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.80M^{-1}s^{-1}

t = time taken  = 95 s

[A] = concentration of substance after time 't' = ?

[A]_o = Initial concentration = 0.86 M

Now put all the given values in above equation, we get:

0.80=\frac{1}{95}\left (\frac{1}{[A]}-\frac{1}{(0.86)}\right)

[A] = 0.013 M

Hence, the concentration of NOBr after 95 s is, 0.013 M

4 0
2 years ago
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