From the pair of values given, the ratio of the volume to the temperature for the first data pair is, 0.0026 cm³/K
<h3>What is a Ratio?</h3>
A ratio is a comparison between two quantities showing how much one quantity differs from another.
From the data given, the first data pair is as follows ;
- Temperature = 276 K
- Volume = 0.72 cm³
Ratio of volume to temperature = volume / temperature
Ratio = 0.72 / 276
Ratio = 0.002608 cm³/K
The significant figure's rule for division is the least number of significant figures used in the operation.
The least significant figure of the values given is 2.
Therefore, the ratio of the volume to the temperature for the first data pair is 0.0026 cm³/K
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<span>From left to right:
1) starts at high pH, no buffer zone - strong base being titrated with strong acid
2) starts at low pH, no buffer zone - strong acid being titrated with strong base
3) starts at low pH, shows a buffer zone - weak acid titrated with strong base
4) starts at high pH, shows a buffer zone - weak base titrated with strong acid
5) polyprotic due to two equivalence points
</span>
Answer:
Heat released =811.68kcal
Explanation:
2 CO(g) + O2(g) → 2 CO2(g) ΔH=-135.28kcal
for this type of question 1st balance the chemical reaction and use unitry method.
From the above balanced equaion it is clearly that,
2 mole of CO reacts with 1 mole of O2 and we have sufficient amount of oxygen means excess amount.
and also for complete consumption of 2 mole of CO, ΔH=-135.28 kcal
for complete consumption of 12 moles of CO2 ΔH=
Heat released =811.68kcal
