5 hope this helps sorry if wrong
Answer:
87
Step-by-step explanation:
For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
Answer:
given n(A) = 14
n(B) = 15
n(A∩B ) = 15
Step-by-step explanation:
now we know that ,n(AUB) = n(A)+n(B)-n(A∩B)
n(AUB) = 14+15-6 = 23.Answer
Answer:
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