Where is the major arc located in a central angle
1 answer:
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Answer:
0 < y <= 6
Step-by-step explanation:
Given:
√(x² - 6x + 9)
if -3 <= x < 3
you can write (x² - 6x + 9)
as (x-3) * (x- 3) which is (x-3)²
so now you have √{(x-3)²}, which is the same as the absolute value of x-3. In mathematics it is written as:
| x - 3 |
So √(x² - 6x + 9) = | x - 3 |
See the graph in the attachment.
for -3 <= x < 3
you get the y values bigger then ( but not equal to) 0 and smaller then or equal to 6.
This is written as 0 < y <= 6
