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3 years ago

Explain what will happen when cold water is placed in a sealed room after an amount of time and what type of system is it ?

Chemistry

1 answer:

ArbitrLikvidat [17]3 years ago

5 0

Answer:

- Water's temperature will be in equilibrium with the surrounding temperature.

- Closed system.

Explanation:

Hello,

In this case, in thermodynamics we define a sealed room as a closed system (matter neither leaves nor enters to the system) which allows the energy transfer as it is not isolated. In such a way, as time goes by, the water will exchange energy with the surroundings in order to attain the thermal equilibrium (equal temperature for both water and surroundings). Thus, if the surroundings are hotter than the cold water, it will heat up until equilibrium temperature. Moreover, if the surroundings are colder than the water, it will cool down until equilibrium temperature.

Best regards.

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The following equation lnN - N₀ = -kt Of time t is plotted on x-axis and lnN is plotted on y-axis, what are the slopes and y-int

stepladder [879]

Answer:

-k slope

The term No is the y intercept(does not mean NO) y-intercept

Explanation:

For a straight line graph, the normal equation could be written as

y = mx + c

Where m is the slope and c is the y intercept.

Writing the equation is the form of y = mx + c gives the following;

lnN = -kt + No

As obtained from the question, t is plotted in the x-axis, while lnN is the plot on the y-axis.

Now, we are asked to obtain the slope and the y-intercept. It can be seen that the slope is the coefficient of the term x in this case t. Hence, our slope is -k.

The y-intercept is the other term which in this case is No

6 0

3 years ago

5K + KNO3 ------ 3K2O + N

masya89 [10]

Answer:

174,957.143 grams of potassium and 89,228.478 grams of potassium nitrate will be needed.

Explanation:

$5K +KNO_3\rightarrow 3K_2O + N$

Mass of nitrogen = 27 lbs = 12,247 g

1 lbs = 453.592 g

Moles of nitrogen = $\frac{12,247 g}{14 g/mol}=874.786 mol$

According to reaction, 1 mole of nitrogen is produced from 5 moles of potassium and 1 mole of potassium nitrate.

Then 874.786 mol of nitrogen will be obtained from :

$\frac{5}{1}\times 874.786 mol=4,373.928 mol$ of potassium.

Then 874.786 mol of nitrogen will be obtained from :

$\frac{1}{1}\times 874.786 mol=874.789 mol$ of potassium nitrate.

Mass of 4,373.928 moles of potassium:

$4,373.928 mol\times 40 g/mol=174,957.143 g$ of potassium

Mass of 874.789 moles of potassium nitrate:

$874.789 mol\times 102 g/mol=89,228.478 g$ of potassium nitrate

3 0

3 years ago

For the reaction, calculate how many moles of the product form when 0.016mol of O2 completely reacts. . Assume that there is mor

Oksi-84 [34.3K]

The balanced reaction is given as:

2Ca(s)+O2(g)→2CaO(s)

We are given the amount of oxygen gas to be used for the reaction. This will be the starting point of our calculations.

0.016 mol O2 ( 2 mol CaO / 1 mol O2 ) = 0.032 mol CaO

Therefore, for the reaction, the amount of calcium oxide produced is 0.032 moles.

4 0

3 years ago

Please Help! Let P and V represent the pressure and volume of Xe(g). If a piston is used to reduce the volume of the gas to V/2

Elza [17]

1) 2P

2) Average speed does not change

Explanation:

To solve the first part of the problem, we can use Boyle's Law, which states that:

"For a fixed mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"

Mathematically:

$pV=const.$

where

p is the pressure of the gas

V is its volume

For the Xe gas in this problem we can write

$p_1 V_1 = p_2 V_2$

where:

$p_1 = P$ is the initial pressure

$V_1=V$ is the initial volume

$V_2=\frac{V}{2}$ is the final volume

Solving for p2, we find the final pressure:

$p_2=\frac{P V_1}{V_2}=\frac{pV}{V/2}=2P$

So, the pressure has doubled.

The average speed of the atoms/molecules in the gas is given by the formula

$v_{rms}=\sqrt{\frac{3RT}{M}}$

where

R is the gas constant

T is the absolute temperature (in Kelvin) of the gas

M is the molar mass of the gas

$v_{rms}$ is known as rms speed of the particles in the gas

From the formula, we see that the speed of the atoms in the gas depends only on the temperature of the gas.

In the Xe(g) gas in this problem, the temperature is kept constant; therefore, since nothing changes in the formula, this means that the average speed also does not change.

8 0

4 years ago

Answer the following questions.

maw [93]

The mole ratio can be seen below and the volume of each precipitate is 60 mL.

A mole ratio refers to a conversion factor that compares the quantities of two chemicals in moles in a chemical laboratory experiment.

Mole ratio For 1:

= 10 mL : 50 mL
= 1 : 5 mL

Mole ratio For 2:

15 mL : 45 mL
= 1 : 3 mL

Mole ratio For 3:

20 mL : 40 mL
1 : 2 mL

Mole ratio For 4:

30 mL : 30 mL
1 mL : 1 mL

Mole ratio For 5:

40 mL : 20 mL
2 : 1 mL

Mole ratio For 6:

45 mL : 15 mL
3 : 1 mL

Mole ratio For 7:

50 mL : 10 mL
5 : 1 mL

Since the parameters from the left side of the diagram are not shown, we will assume that the volumes for each precipitate are the addition of both volumes in each column.

By doing so, we have:

(10 +50) mL = 60 mL

(15 + 45) mL = 60 mL

(20 + 40)mL = 60 mL

(30 + 30) mL = 60 mL

(40 + 20)mL = 60 mL

(45 + 15) mL = 60 mL

(50 + 10)mL = 60 mL

Learn more about mole ratio here:

brainly.com/question/19099163

7 0

3 years ago