The normal boiling point of cyclohexane is 81.0. What is the vapor pressure of cyclohexane at 81.1
1 answer:
Answer:
1 atm
Explanation:
The normal boiling point of a liquid is temperature at which the vapour pressure of the liquid equals 1 atm.
If the normal boiling point of cyclohexane is 81.0 °C, the vapour pressure of the liquid is 1 atm.
The graph below shows that the vapour pressure of cyclohexane reaches 1 atm at about 81 °C.
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Answer:
4.2 m
Explanation:
The energy (E) of the selector region of the spectrometer is:
E = v*B (equation 1)
Where v is the velocity, and B the magnetic field.
The force with which particle forms a curved path can be calculated by:
Where r is the radius of the particle, m is the mass, and q the electric charge. So:
For equation 1: v = E/B, so:
The two species will be separated by Δr = 0.42 mm
Δr = Δm*E/(q*B*B')
E/(q*B*B') = r/m
Δr = Δm*r/m
r = m*Δr/Δm
r is the large of curvature, m is the avarege mass = (28.0106 + 28.0134)/2 = 28.012:
r = (28.012*0.42)/(28.0134 - 28.0106)
r = 11.76504/(0.0028)
r = 4201.8 mm
r = 4.2 m