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Rainbow [258]
3 years ago
12

Ammonia is the most common and well-known weak base. A sample of household ammonia has a pH of 11.8. Determine its concentration

Chemistry
2 answers:
IrinaK [193]3 years ago
8 0

Answer:

The concentration is 1.58*10^-12 M

Explanation:

Step 1: Data given pH of ammonia = 11.8

pH = -log[H+] = -log[H3O+]

Step 2: Calculate the concentration

2H20(l) ⇆ H3O+ + OH-

Kw = [H3O+][OH-]

-pKw = log[H3O+] + log[OH-] = log 10^-14

-14 = log[H3O+] + log [OH-]

14 = - log[H3O+] - log[OH-]

14 = pH + pOH

[H3O+] = 10^-11.8

[H3O+] = [H+] = 1.58 * 10^-12 M

The concentration is 1.58*10^-12 M

Galina-37 [17]3 years ago
7 0

The given question is incomplete. The complete question is:

A sample of household ammonia has a pH of 11.50. What is the hydronium ion concentration of this solution?

Answer: The hydronium ion concentration of the solution is 1.58\times 10^{-12}M

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration. Acids have pH ranging from 1 to 6.9 and bases have pH ranging from 7.1 to 14.

NH_3+H_2O\rightarrow NH_4^++OH^-

pH=-\log [H^+]

11.8=-log [H^+]

[H^+]=antilog(-11.8)

[H^+]=1.58\times 10^{-12}M

Thus hydronium ion concentration of this solution is 1.58\times 10^{-12}M

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What volume is occupied by 3.760 g of oxygen gas at a pressure of 88.4
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Answer:

3.2 L

Explanation:

Given data:

Mass of oxygen = 3.760 g

Pressure of gas = 88.4 Kpa (88.4×1000 = 88400 Nm⁻²)

Temperature = 19°C (19+273.15 = 292.15 K)

R = 8.314 Nm K⁻¹ mol⁻¹

Volume occupied = ?

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Number of moles of oxygen:

Number of moles = mass/ molar mass

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The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant

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V = nRT/P

V = 0.12 mol ×  8.314 Nm K⁻¹ mol⁻¹ × 292.15 K /88400 Nm⁻²

V = 291.472 Nm /88400 Nm⁻²

V = 0.0032 m³

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V = 0.0032×1000 = 3.2 L

4 0
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