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lys-0071 [83]
4 years ago
7

A polynomial function has a root of 5 with multiplicity 3, a root of 1 with multiplicity 2, and a root of 3 with multiplicity 7.

If th
function has a negative leading coefficient and is of even degree, which statement about the graph is true?
O The graph of the function is positive on (-0, -5).
O The graph of the function is negative on (-5, 3)!
O The graph of the function is positive on (-0, 1).
O The graph of the function is negative on (3,co).
Mathematics
1 answer:
zepelin [54]4 years ago
5 0

Answer:

The graph of the function is negative on (3,0)

Step-by-step explanation:

The limiting behavior of a function describes how a function behaves as x ⇒ ±∞. Its behavior is determined by the degree of a polynomial and the sign of its leading coefficient.

Since the function [f(x)] is an even degree polynomial with negative leading coefficient, then f(x) ⇒ -∞ as x ⇒ ±∞. The graph of the function is negative at the root. Since it has a root of 3, The graph of the function is negative on (3,0)

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