When you graph an equation, it should be dependent variable against the independent variable. For this problem, the independent variable is the time, so this is along the x-axis. The dependent variable is d, so this is along the y-axis. Since the slope is Δy/Δx, then it is also equivalent to Δd/Δt. Therefore, the answer is B.
The equation of a line that passes through (x1,y1) and has a slope of m is
y-y1=m(x-x1)
find slope
slope between (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
given
(-3,2) and (2,1)
slope=(1-2)/(2-(-3))=(-1)/(2+5)=-1/5
pikc a point
if we pick (-3,2)
(x1,y1)
x1=-3
y1=2
y-2=-1/5(x-(-3))
y-2=-1/5(x+3)
that is D
Answer:
Polynomial equation solver
x-3=3x-2
Standard form:
−2x − 1 = 0
Factorization:
−(2x + 1) = 0
Solutions:
x = −1
2
= -0.5
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Maintaining the same width of the compass as AB, draw an arc from point X such that it intersects the afternoon drawn from N in a point
