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Naily [24]
3 years ago
14

What are the values of a and b?

Mathematics
1 answer:
ivann1987 [24]3 years ago
3 0

Answer:

<h2>a = 400/21, b = 580/21</h2>

Step-by-step explanation:

Small triangles are similar. Therefore, the sides are proportional

\dfrac{a}{20}=\dfrac{20}{21}               <em>cross multiply</em>

21a=(20)(20)       <em>divide both sides by 21</em>

a=\dfrac{400}{21}

For b, we can use the Pythagorean theorem:

b^2=\left(\dfrac{400}{21}\right)^2+20^2\\\\b^2=\dfrac{160000}{441}+400\\\\b^2=\dfrac{160000}{441}+\dfrac{176400}{441}\\\\b^2=\dfrac{336400}{441}\to b=\sqrt{\dfrac{336400}{441}}\\\\b=\dfrac{\sqrt{336400}}{\sqrt{441}}\\\\b=\dfrac{580}{21}

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On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)
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The perimeter of the kite is (10 + 2√53) units if the kite and the coordinates of the kite are point W is at (-3, 3), point X is at (2, 3), point Y is at (4, -4), and point Z is at (-3, -2).

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It is defined as the four-sided polygon in geometry having four edges and four corners. Kite is quadrilateral, in which. Two pairs of congruent sides, and it has one pair of opposite congruent angles.

The figure is missing.

On a coordinate plane, kite WXYZ is shown (please refer to the picture)

We have a kite and the coordinates of the kite are:

Point W is at (-3, 3), point X is at (2, 3), point Y is at (4, -4), and point Z is at (-3, -2).

Using the distance formula we can find the distance between coordinates:

\rm d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between W and X:

\rm WX=\sqrt{(2+3)^2+(3-3)^2}

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Similarly, distance between X and Y:

XY = √53 units

YZ = √53 units

ZW = 5 units

Perimeter = sum of the all sides

Perimeter = 5 + √53 + √53 + 5

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Thus, the perimeter of the kite is (10 + 2√53) units if the kite and the coordinates of the kite are point W is at (-3, 3), point X is at (2, 3), point Y is at (4, -4), and point Z is at (-3, -2).

Learn more about the quadrilateral here:

brainly.com/question/6321910

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