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3 years ago

If there is 3% freshwater available on earth, approximately what percentage of it is in ice?

Chemistry

2 answers:

steposvetlana [31]3 years ago

5 0

1% cuz i thinkkk (I'm not sure)

Crank3 years ago

4 0

I have no idea but if anyone is seeing this PLEASE ANSWER MY WUESTIONS ON MY PAGE i will give you the brainliest

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A student wants to determine if a

Sauron [17]

Answer:

The Density of Magnesium.

Explanation:

7 0

3 years ago

How many moles of ammonium ions are in 125 mL of 1.40 M NH4NO3 solution? ________ moles (give answer with correct sig figs in un

Sholpan [36]

The number of mole of ammonium ion, NH₄⁺ in the solution is 0.175 mole

We'll begin by calculating the number of mole of NH₄NO₃ in the solution. This can be obtained as follow:

Volume = 125 mL = 125 / 1000 = 0.125 L

Molarity = 1.40 M

Mole = Molarity x Volume

Mole of NH₄NO₃ = 1.40 × 0.125

Finally, we shall determine the number of mole of ammonium ion, NH₄⁺ in the solution. This can be obtained as follow:

NH₄NO₃(aq) —> NH₄⁺(aq) + NO₃¯(aq)

From the balanced equation above,

1 mole of NH₄NO₃ contains 1 mole of NH₄⁺

Therefore,

0.175 mole of NH₄NO₃ will also contain 0.175 mole of NH₄⁺

Thus, the number of mole of ammonium ion, NH₄⁺ in the solution is 0.175 mole

Learn more: brainly.com/question/25469095

3 0

2 years ago

Can you Guys please help me on 14,and 15

jok3333 [9.3K]

14. is a and i think 15. is b

7 0

2 years ago

Read 2 more answers

A chunk of tin weighing 18.5 grams and originally at 97.38 °C is dropped into an insulated cup containing 75.7 grams of water at

weqwewe [10]

Answer:

22.44°C will be the final temperature of the water.

Explanation:

Heat lost by tin will be equal to heat gained by the water

$-Q_1=Q_2$

Mass of tin = $m_1=18.5 g$

Specific heat capacity of tin = $c_1=0.21 J/g^oC$

Initial temperature of the tin = $T_1=97.38^oC$

Final temperature = $T_2$ =T

$Q_1=m_1c_1\times (T-T_1)$

Mass of water= $m_2=75.7 g$

Specific heat capacity of water= $c_2=4.184 J/g^oC$

Initial temperature of the water = $T_3=21.52^oC$

Final temperature of water = $T_2$ =T

$Q_2=m_2c_2\times (T-T_3)$

$-Q_1=Q_2$

$-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)$

On substituting all values:

$-(18.5 g\times 0.21 J/g^oC\times (T-97.38^oC))=75.7 g\times 4.184 J/g^oC\times (T-21.52 ^oC)$

we get, T = 22.44°C

22.44°C will be the final temperature of the water.

5 0

3 years ago

Pls assist if you can.<br>Reasons why hydrogen was chosen as a standard reference to other elements

MrMuchimi

Answer:

See below

Step-by-step explanation:

Hydrogen either reacts with or is formed by reactions with many other elements, so chemists could use it directly to determine their relative masses.
Hydrogen has the smallest atomic mass, so it was convenient to give H a relative atomic mass of 1 and assign those of other elements as multiples of this number.

The O = 16 scale became the standard in 1903 and carbon-12 was chosen in 1961.

4 0

3 years ago