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sertanlavr [38]
3 years ago
11

Formula for dicyanoargentate (I) ion​

Chemistry
1 answer:
sergey [27]3 years ago
7 0

Answer:

Potassium dicyanoargentate(I) | C2AgKN2 - PubChem.

Synonyms: Potassium dicyanoargentate(I)pota...

Molecular Formula: C2AgKN2

Explanation:

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Magnesium has three naturally occurring isotopes with masses of 23.99 amuamu, 24.99 amuamu, and 25.98 amuamu and natural abundan
bonufazy [111]

Answer:

24.309 g/mol

Explanation:

To get the atomic mass, all we have to do is calculate with the masses of the three isotope, the real quantity present, taking account of the percent and then, do a sum of these three values. Like a pondered media.

For the first isotope:

23.99 * (78.99/100) = 18.95 g/mol

For the second isotope:

24.99 * (10/100) = 2.499 g/mol

For the last isotope:

25.98 * (11.01/100) = 2.86 g/mol

Now, let's sum all three together

AW = 18.95 + 2.499 + 2.86

AW = 24.309 g/mol

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4 years ago
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<span>Thermal energy is the energy that comes from heat. This heat is generated by the movement of tiny particles within an object. The faster these particles move, the more heat is generated.</span>

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An object is either copper or brass. The density of copper is 8.96g/ml. The density of brass is 8.73g/mL. I find that my object
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Calculate the concentration, in moles per litre, of a solution formed when 13.0 g of calcium hydroxide is dissolved in 5.0 L. Pl
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Answer: The concentration, in moles per litre, of a solution formed when 13.0 g of calcium hydroxide is dissolved in 5.0 L is 0.036 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

moles of Ca(OH)_2 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{13.0g}{74g/mol}=0.18mol

Now put all the given values in the formula of molality, we get

Molarity=\frac{0.18}{5.0L}=0.036M

Therefore, the concentration, in moles per litre, of a solution formed when 13.0 g of calcium hydroxide is dissolved in 5.0 L is 0.036 M

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