The given
ketone when reacted with base gave
enolate, the enolate formed due to loss of
methylene proton next to carbonyl group. Enolate when treated with
methyle Bromide gave
alpha substituted product.
Strong absorption around 1713 cm⁻¹ in IR spectrum confirms the presence of
Carbonyl group.
The product along with
¹H-NMR values is given below,
Main Answer:
Given
pH = -log[H+]
= -log[0.00017]
= 3.769
We know that
pW = pH + pOH
and pW =14
pOH = 14-pH
=14-3.769
=10.231
According to the definition
pOH = -log[OH-]
10.231 = log[OH-]-1
[OH-]= 5.87 x 10-11
Explanation:
What is pH?
pH is defined as the concentration of H+ ion in the solution. If the pH value is less than 7, then the solution will be acidic. If the pH value is greater than 7, then the solution will be basic.
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Answer: (1)CaSO4 -> (2)O2 + (1)CaS
Explanation: edge 2020 chem
I think the answer is ‘repulsion’