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3 years ago

How do wetlands form?

Chemistry

2 answers:

jarptica [38.1K]3 years ago

8 0

Constant rain and humidity

Marianna [84]3 years ago

4 0

Wetlands form where water and land meet. These may be glacial potholes, or old lake beds where water is semi-permanent, being wet in the rainy season and dry the rest of the year. They may be at the fringe of permanent bodies of water. They may be low lying places that fill with water when the water table rises.

Wetlands change over time. A lake with a wetland fringe can fill in with decayed plant and animal material to become a wet meadow. A pond can fill in to become a bog or fen. Sediment can fill in a river marsh to become a swamp. A flood can scour out soil and turn a marsh into open water.

definition of wetlands, characteristics of wetlands, types of wetlands, change over time, functions of wetlands, man-made wetlands,project

Explanation:No explanation plz give me brainiest

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3 years ago

Determine the limiting reactant when 30.0 g of propane, C3H8, is burned with 75.0 g of oxygen.

AnnZ [28]

Answer: The limiting reagent is oxygen gas.

Explanation:

Limiting reagent is defined as the reactant that is present in less amount and it limits the formation of products.

Excess reagent is defined as the reactant which is present in large amount.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For propane:

Given mass of propane = 30.0 g

Molar mass of propane = 44.1 g/mol

Putting values in equation 1, we get:

$\text{Moles of propane}=\frac{30.0g}{44.1g/mol}=0.680mol$

For oxygen:

Given mass of oxygen = 75.0 g

Molar mass of oxygen = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of propane}=\frac{75.0g}{32g/mol}=2.34mol$

The chemical equation for the combustion of propane follows:

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(l)$

By Stoichiometry of the reaction:

5 moles of oxygen gas reacts with 1 mole of propane.

So, 2.34 moles of oxygen gas will react with = $\frac{1}{5}\times 2.34=0.468mol$ of propane

As, given amount of propane is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reagent is oxygen gas.

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3 years ago

For a science experiment Marcia dissolved 1.0 kilogram of salt in 3.0 liters of water. For a different experiment, Bobby dissolv

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Answer: Marcia made a more concentrated salt solution.

Explanation:

Marcia used 1 kg of salt, which the exercise tells us is 2.2 lb.

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If 1L equals 2.11 pints, then

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Now we know she dissolved 2.2lb in 6.33 pints of water. We use cross multiplication again to find out how much salt she would have in 10 pints, so we can know how concentrated it is compared to Bobby's solution, which is 10 pints.

xlb / 10pints = 2.2lb / 6.33pints

xlb = (10pints . 2.2lb) / 6.33pints = 3.47lb

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