Answer:
6.022×1023 individual items of that something. You have 3 moles, so there are 3×6.022×1023 oxygen molecules
Explanation:
6.022×1023 individual items of that something. You have 3 moles, so there are 3×6.022×1023 oxygen molecules
Answer:
The cylindrical tube can hold 0.215 cubic decimeters of blood.
Explanation:
Diameter of the cylindrical tube = d = 4.5 cm
r = d/2 ,r = 2.25 cm
Height of the cylindrical tube = h = 13.5 cm
Volume of the cylinder = V =
The cylindrical tube can hold 0.215 cubic decimeters of blood.
Answer:
The voltage is
Explanation:
Since the main source of is the sea water then
The equation for the reaction in sea water would be
that is the ion would form a molecule and then release an electron
For river water
I.e the molecule would gain an electron and forms an ion
Now acts as reactant for seawater reaction and product for river water
The voltage of the concentration cell at initial stage is
Now at the voltage for the cell with concentration difference between sea water and river water is mathematical denoted as
Where is the number of electron = 1
So substituting values we have
Removing the negative sign
Answer:
gas to solid
Explanation:
Exothermic means the release of heat. Any transformation from a less ordered to a more ordered state releases energy. This is represented by the change of a liquid to solid, gas to liquid, or gas to solid. Vise versa endothermic is the transformation from a more ordered state to a less ordered state represented by solid to liquid, liquid to gas, and solid to gas.
Answer:
At the cathode in an electrolytic cell, ions in the surrounding solution are reduced into atoms, which precipitate or plate out on to the solid cathode. The anode is where oxidation takes place, and the cathode is where reduction takes place. The anode is defined as the electrode where oxidation occurs. The cathode is the electrode where reduction takes place. ... At the cathode, the metal ion in the solution will accept one or more electrons from the cathode, and the ion's oxidation state will reduce to 0. This forms a solid metal that deposits on the cathode.