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Musya8 [376]
1 year ago
11

Determine, to the nearest tenth of a year, how long it would taken an investment to double at a 3 3/4% interest rate, compounded

continuously
Mathematics
1 answer:
Stella [2.4K]1 year ago
7 0

Based on the interest rate and continuous compounding, the investment would double in value after 18.5 years.

We have given that,

investment to double at a 3 3/4% interest rate,

<h3>When will the investment double in value?</h3>

The future value using continuous compounding is:

= Amount x e ^ (rate x time)

Interest is

= 3.75%

<h3>What is the formula of an exponential function?</h3>

2 = e ^ (0.0375 x time)

In2 = 0.0375 x time

t = In2 / 0.0375

t= 18.5 years

To learn more about the compounded continuously visit:

brainly.com/question/16731646.

#SPJ1

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15. If x=a Sin2t (I+Cos2t) and y=b Cos 2t (1-Cos2t) then find<br>dy/dx at =22/7*4<br>​
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By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}

It looks like we're given

\begin{cases}x=a\sin(2t)(1+\cos(2t))\\y=b\cos(2t)(1-\cos(2t))\end{cases}

where <em>a</em> and <em>b</em> are presumably constant.

Recall that

\cos^2t=\dfrac{1+\cos(2t)}2

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so that

\begin{cases}x=2a\sin(2t)\cos^2t\\y=2b\cos(2t)\sin^2t\end{cases}

Then we have

\dfrac{\mathrm dx}{\mathrm dt}=4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t

\dfrac{\mathrm dy}{\mathrm dt}=-4b\sin(2t)\sin^2t+4b\cos(2t)\sin t\cos t

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4b\cos(2t)\sin t\cos t-4b\sin(2t)\sin^2}{4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t}

\implies\boxed{\dfrac{\mathrm dy}{\mathrm dx}=\dfrac ba\tan t}

where the last reduction follows from dividing through everything by \cos(2t)\cos^2t and simplifying.

I'm not sure at which point you're supposed to evaluate the derivative (22/7*4, as in 88/7? or something else?), so I'll leave that to you.

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What two numbers multiply to get 25 and add to -10
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