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MrRissso [65]
3 years ago
9

How is 0.246¯¯¯¯ written as a fraction in simplest form?

Mathematics
2 answers:
Tresset [83]3 years ago
7 0

Answer:

The answer in simplest fraction form is

\frac{1}{4}

Step-by-step explanation:

0.246 rounded up because after the 4 is a 6 so that means you round up making it 0.25

san4es73 [151]3 years ago
6 0

Answer:

1000÷246=500÷123

Step-by-step explanation:

the answer is 500÷123

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The surface area of a cylinder
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4 years ago
PLEASE HELP!! what is the equation for the parabolic function that goes through the points (-3, 67) (-1, 1) and has a stretch fa
barxatty [35]

Answer:

f(x)=9(x+\frac{1}{6})^2-\frac{21}{4}

Step-by-step explanation:

So, we need to find the equation of a parabolic function that goes through the points (-3,67) and (-1,1) and has a stretch factor of 9.

In other words, we want to find a quadratic with a vertical stretch of 9 that goes through the points (-3,67) and (-1,1).

To do so, we first need to write some equations. Let's use the vertex form of the quadratic equation. The vertex form is:

f(x)=a(x-h)^2+k

Where a is the leading coefficient and (h,k) is the vertex.

Since a is the leading coefficient, it's also our stretch factor. Thus, let a equal 9.

Also, we have two points. We can interpret them as functions. In other words, (-3,67) means that f(-3) equals 67 and (-1,1) means that f(-1) equals 1. Write the two equations:

f(x)=a(x-h)^2+k\\f(-3)=67=9((-3)-h)^2+k

And:

f(x)=a(x-h)^2+k\\f(-1)=1=9((-1)-h)^2+k

Now, we essentially have a system of equations. Thus, to find the original equation, we just need to solve for the vertex. To do so, first isolate the k term in the second equation:

1=9(-1-h)^2+k\\k=1-9(-1-h)^2

Now, substitute this value to the first equation:

67=9(-3-h)^2+k\\67=9(-3-h)^2+(1-9(-1-h)^2)

And now, we just have to simplify.

First, from each of the square, factor out a negative 1:

67=9((-1)(h+3))^2+(1-9(((-1)(h+1))^2)

Power of a product property:

67=9((-1)^2(h+3)^2)+(1-9((-1)^2(h+1)^2))

The square of -1 is positive 1. Thus, we can ignore them:

67=9(h+3)^2+(1-9(h+1)^2)

Square them. Use the trinomial pattern:

67=9(h^2+6h+9)+(1-9(h^2+2h+1))

Distribute:

67=(9h^2+54h+81)+(1-9h^2-18h-9)

Combine like terms:

67=(9h^2-9h^2)+(54h-18h)+(81+1-9)

The first set cancels. Simplify the second and third:

67=36h+73

Subtract 73 from both sides. The right cancels:

67-73=36h+73-73\\36h=-6

Divide both sides by 36:

(36h)/36=(-6)/36\\h=-1/6

Therefore, h is -1/6.

Now, plug this back into the equation we isolated to solve for k:

k=1-9(-1-h)^2

First, remove the negative by simplifying:

k=1-9((-1)(h+1))^2\\k=1-9((-1)^2(h+1)^2)\\k=1-9(h+1)^2

Plug in -1/6 for h:

k=1-9(-\frac{1}{6}+1)^2

Add. Make 1 into 6/6:

k=1-9(-\frac{1}{6}+\frac{6}{6})^2\\  k=1-9(\frac{5}{6})^2

Square:

k=1-9(\frac{25}{36})

Multiply. Note that 36 is 9 times 4:

k=1-9(\frac{25}{9\cdot4})\\ k=1-\frac{25}{4}

Convert 1 into 4/4 and subtract:

k=\frac{4}{4}-\frac{25}{4}\\  k=-\frac{21}{4}

So, the vertex is (-1/6, -21/4).

Now, plug everything back into the very original equation with 9 as a:

f(x)=a(x-h)^2+k\\f(x)=9(x+\frac{1}{6})^2-\frac{21}{4}

And this is our answer :)

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3 years ago
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What is
krok68 [10]
If the lines were parallel they would have the same slope. if the lines were perpendicular then the slope would be the negative reciprocal slope. The answer to your question would be -3/7.
6 0
3 years ago
Solve the system of equations by substitution. What is the solution for x?
Nostrana [21]

Answer:

There is no x value, as there is no solution

Step-by-step explanation:

we have

2x+y=1

Isolate the variable y

y=-2x+1 -----> equation A

4x+2y=-1 ---> equation B

Solve the system of equations by substitution

Substitute the equation A in the equation B and solve for x

4x+2(-2x+1)=-1

4x-4x+2=-1

2=-1 ------> is not true

therefore

The system has no solution

Equation A and equation B are parallel lines with different y-intercepts

7 0
4 years ago
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