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tatuchka [14]
3 years ago
13

What’s the correct answer for this?

Mathematics
1 answer:
Yuri [45]3 years ago
6 0

Answer:

B

Step-by-step explanation:

In the attached file

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If 180 kg of sugar is to be divided into 3 quantities of ratio 2:3:4 find the smallest and largest quantities.​
steposvetlana [31]

Answer:

smallest amount of sugar = 40 kg

largest amount of sugar = 80 kg

Step-by-step explanation:

2 : 3 : 4

2 + 3 + 4 = 9

180 ÷ 9 = 20

Therefore,

2 : 3 : 4 = (2 x 20) : (3 x 20) : (4 x 20) = 40 : 60 : 80

So the smallest amount of sugar = 40 kg

and the largest amount of sugar = 80 kg

4 0
2 years ago
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On a bike trip, you traveled 21 miles on
Tasya [4]

Answer:

She traveled 13 23/56 miles on the third day.

Step-by-step explanation:

HOPE THIS HELPED ;3

5 0
2 years ago
What is the expansion of (3+x)^4
Vlad1618 [11]

Answer:

\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81

Step-by-step explanation:

Considering the expression

\left(3+x\right)^4

Lets determine the expansion of the expression

\left(3+x\right)^4

\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i

a=3,\:\:b=x

=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i

Expanding summation

\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}

i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0

i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1

i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2

i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3

i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

as

\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81

\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x

\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2

\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3

\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4

so equation becomes

=81+108x+54x^2+12x^3+x^4

=x^4+12x^3+54x^2+108x+81

Therefore,

  • \left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81
6 0
3 years ago
For points on a graph chart, do you go over then up or up then over?
dusya [7]
You have to go over then up (x,y)
3 0
3 years ago
suzie spent 3 1/2 hours at the beach. she spent 45 minutes playing in the sand and the rest of the time playing in the water. ho
Anika [276]

Answer:

2 hours and 45 min

Explanation:

3 hours+30 minutes

subtract 30

3 hours

subtract 15

2 hours and 45 min

6 0
2 years ago
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