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-Dominant- [34]
3 years ago
7

Answer ASAP

Mathematics
2 answers:
Delvig [45]3 years ago
6 0
Yea I’m pretty sure that the answer is d
marta [7]3 years ago
4 0

Answer:

D

Step-by-step explanation:

You might be interested in
List the first 5 terms of the sequence -3n -2.<br>​
katrin2010 [14]

Answer:

-5,-8,-11,-14,-17

Step-by-step explanation:

-3n -2

n=1   -3(1) -2 = -3-2 = -5

n=2   -3(2) -2 = -6-2 = -8

n=3   -3(3) -2 = -9-2 = -11

n=4   -3(4) -2 = -12-2 = -14

n=5   -3(5) -2 = -15-2 = -17

7 0
3 years ago
Read 2 more answers
(14v^7x^2-3v^7x^5)divided by (-2v^4x^3)
Dmitrij [34]

.1 Simplify: 5n(2n3+n2+8)+n(4-n).

Solution:

5n(2n3+n2+8)+n(4-n).

= 5n × 2n3 + 5n × n2 + 5n × 8 + n × 4 - n × n.

= 10n4 + 5n3 + 40n + 4n – n2.

= 10n4 + 5n3 + 44n – n2.

= 10n4 + 5n3 – n2 + 44n.

Answer: 10n4 + 5n3 – n2 + 44n

5 0
2 years ago
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0
2 years ago
I don’t wanna fail if you know the answer pls help me :(
devlian [24]

Answer: 0.0083

              0.00083

              0.000083

Step-by-step explanation: hope it helps

3 0
2 years ago
Read 2 more answers
Rewrite each expression as a polynomial in standard form.a)(x+i)(x-i)b)(x+5i)(x-5i)
Nitella [24]

Answer:

a) x² +1

b) x² +25

Step-by-step explanation:

a) (x+i)(x− i)

   = x² - ( i ) x + ( i ) x - ( i)²

   = x² -  i²                       ∵ i² = -1

   = x² -  (-1)

   = x² +1

b) (x+5 i)(x− 5i)

 = x² - ( 5 i ) x + ( 5 i ) x - ( 5 i)²

   = x² - 25 i²                       ∵ i² = -1

   = x² -  25(-1)

   = x² +25

we can also solve

using identity

   (a + b)(a - b) = a² - b²

   = (x+5 i)(x− 5i)    

   = x² - (5 i)²

   = x² - 25 i²

   = x² +25

8 0
3 years ago
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