Question

Solve for x in the equation 3x^2-18+5=47​

Answer 1

Answer:

$\sqrt{20}$

Step-by-step explanation:

Try to leave x alone on the left side

$3x^{2} -18 + 5 = 47$

$3x^{2} -13 = 47$

To leave alone x, add +13 to both sides. Because left side has -13

$3x^{2} -13 + 13 = 47 + 13$

$3x^{2} = 60$

Now x is alone on the  left side

$\frac{3x^{2} }{3} = \frac{60}{3}$

$x^{2} = 20$

• $\sqrt{x} .\sqrt{x} = x$  <=Rule

So; x=$\sqrt{20}$

Hope this helps ^-^