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zalisa [80]
4 years ago
5

Please help! Will give brainliest!

Mathematics
1 answer:
Zanzabum4 years ago
6 0

Answer:

Step-by-step explanation:

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I really need help with solving x please
Luba_88 [7]
From the fact that the shape is a square, we know that one of the angles of the triangle in question must by 90 degrees (the lower left angle in this case). 

The triangle formed is also an isosceles triangle and therefore the two smaller angles must be equal to each other. (upper left and lower right) 

On top of this, we also know that the total of the angles must be 180 due to the fact that all triangles have interior angles that add to 180.

90 + (lower right) + (upper left) = 180

Since lower right and upper left are equal, we can use a single variable to represent them both.

90 + a + a = 180
90 + 2a = 180
2a = 90
a = 45
So, the degree of the lower right angle is 45. We can take this value and set 4x + 17 equal to it.

4x + 17 = 45
4x = 28
x = 7

Therefore, x is equal to 7.
5 0
3 years ago
Which deal is the better buy? 2 for $24.99 or 5 for $58.99
HACTEHA [7]
Buy 2 for$ 24.99 depends on what your getting 
6 0
3 years ago
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A plane can fly 540 miles with the wind in one hour less than it can fly 480 miles against the wind. The average wind speed is 3
Bess [88]

Answer:

The speed of the plane in still air = 150 mph

Step-by-step explanation:

This is a relative velocity question

Let the velocity of the plane in still air be v

And let the time the plane can fly 480 miles against the wind be t

(Velocity of the plane relative to the wind) = (velocity of plane) - (velocity of wind)

Flying against the wind

(Velocity of plane relative to the wind) = (480/t)

(Velocity of the plane) = v

(Velocity of the wind) = 30 mph

(480/t) = v - 30

t = 480/(v-30) (eqn 1)

Flying with the wind

(Velocity of plane relative to the wind) = 540/(t-1)

(Velocity of the plane) = v

(Velocity of the wind) = -30 mph

540/(t - 1) = v + 30

t - 1 = 540/(v+30) (eqn 2)

Since t is equal in both cases, substitute the value of t in eqn 1 into eqn 2.

[480/(v-30)] - 1 = [540/(v+30)]

Multiply through by (v+30)(v-30)

480(v+30) - [(v+30)(v-30)] = 540(v-30)

480v + 14400 - (v² - 900) = 540v - 16200

480v + 14400 - v² + 900 = 540v - 16200

v² + 540v - 480v - 16200 - 14400 - 900 = 0

v² + 60v - 31500 = 0

Solving the quadratic equation,

v = 150 mph or v = -210 mph

We'll pick the positive answer because of the directions we have established.

Therefore, the speed of the plane in still air = 150 mph

Hope this Helps!!!

3 0
3 years ago
Is 60n + 12 equal to 12(5n + 1)
hram777 [196]

Answer: no

Step-by-step explanation:

5 0
3 years ago
Which graph represents the solution set of the system of inequalities? {x+y<12 y≥x−4
RSB [31]

Answer: The graph in the bottom right-hand corner

(see figure 4 in the attached images below)

===========================================

Explanation:

Let's start off by graphing x+y < 1. The boundary equation is x+y = 1 since we simply change the inequality sign to an equal sign. Solve for y to get x+y = 1 turning into y = -x+1. This line goes through (0,1) and (1,0). The boundary line is a dashed line due to the fact that there is no "or equal to" in the original inequality sign. So x+y < 1 turns into y < -x+1 and we shade below the dashed line. The "less than" means "shade below" when y is fully isolated like this. See figure 1 in the attached images below.

Let's graph 2y >= x-4. Start off by dividing everything by 2 to get y >= (1/2)x-2. The boundary line is y = (1/2)x-2 which goes through the two points (0,-2) and (4,0). The boundary line is solid. We shade above the boundary line. Check out figure 2 in the attached images below.

After we graph each individual inequality, we then combine the two regions on one graph. See figure 3 below. The red and blue shaded areas in figure 3 overlap to get the purple shaded area you see in figure 4, which is the final answer. Any point in this purple region will satisfy both inequalities at the same time. The solution point cannot be on the dashed line but it can be on the solid line as long as the solid line is bordering the shaded purple region. Figure 4 matches up perfectly with the bottom right corner in your answer choices.

5 0
3 years ago
Read 2 more answers
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