Answer: 
Center = (2, 3) radius = 
<u>Step-by-step explanation:</u>
When both the x² and y² values are equal and positive, the shape is a circle. Complete the square to put the equation in format:
(x-h)² + (y-k)² = r² where
- (h, k) is the vertex
- r is the radius
1) Group the x's and y's together and move the number to the right side
4x² - 16x + 4y² - 24y = -51
2) Factor out the 4 from the x² and y²
4(x² - 4x ) + 4(y² - 6y ) = -51
3) Complete the square (divide the x and y value by 2 and square it)
![4[x^2-4x+\bigg(\dfrac{-4}{2}\bigg)^2]+4[y^2-6y+\bigg(\dfrac{-6}{2}\bigg)^2]=-51+4\bigg(\dfrac{-4}{2}\bigg)^2+4\bigg(\dfrac{-6}{2}\bigg)^2](https://tex.z-dn.net/?f=4%5Bx%5E2-4x%2B%5Cbigg%28%5Cdfrac%7B-4%7D%7B2%7D%5Cbigg%29%5E2%5D%2B4%5By%5E2-6y%2B%5Cbigg%28%5Cdfrac%7B-6%7D%7B2%7D%5Cbigg%29%5E2%5D%3D-51%2B4%5Cbigg%28%5Cdfrac%7B-4%7D%7B2%7D%5Cbigg%29%5E2%2B4%5Cbigg%28%5Cdfrac%7B-6%7D%7B2%7D%5Cbigg%29%5E2)
= 4(x - 2)² + 4(y - 3)² = -51 + 4(-2)² + 4(-3)²
= 4(x - 2)² + 4(y - 3)² = -51 + 4(4) + 4(9)
= 4(x - 2)² + 4(y - 3)² = -51 + 16 + 36
= 4(x - 2)² + 4(y - 3)² = 1
4) Divide both sides by 4

- (h, k) = (2, 3)

Answer:
Explanation:
We can factor the numerator and denominator as;
(
x
−
2
)
(
x
−
1
)
2
x
(
x
−
1
)
We can now cancel common term in the numerator and denominator:
(
x
−
2
)
(
x
−
1
)
2
x
(
x
−
1
)
⇒
x
−
2
2
x
However, we cannot divide by
0
so we must exclude:
2
x
=
0
⇒
x
=
0
and
x
−
1
=
0
⇒
x
1
x
2
−
3
x
+
2
2
x
2
−
2
x
=
x
−
2
2
x
Where:
x
≠
0
and
x
≠
1
Or
x
2
−
3
x
+
2
2
x
2
−
2
x
=
x
2
x
−
2
2
x
=
1
2
−
1
x
Where:
x
≠
0
and
x
≠
1
Step-by-step explanation:
Answer:
congruent SAS
Step-by-step explanation:
We know two sides of the triangles are congruent to each other
MD = MT
and MA = MU
We also know that <DMA = < TMU
Two sides and the included angle
We can use SAS to show that the triangles are congruent
Answer:
i wish i could help but its kind of over a minute but the answer is C
Answer:
50
Step-by-step explanation:
trust me bro