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nignag [31]
3 years ago
5

What is an unifying characteristic of all crustaceans?

Biology
1 answer:
WINSTONCH [101]3 years ago
3 0

Answer:

A hard exoskeleton made of calcium - no internal skeleton. The head has two compound eyes, two pairs of antennae, and three pairs of mouthparts. A pair of green glands excrete wastes near the base of antennae. The abdominal segments have swimmerets (swimming legs)

Explanation:

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A one-hectare pond is sampled in early September. The sample yields 1 small catfish as well as 17 benthic invertebrates that rep
zaharov [31]

Answer:

e.) the biodiversity of the pond has decreased

Explanation:

Biodiversity or biological diversity refers to the variety of living organisms in a particular area. It can be a measure of number of species of living organisms in that area. The more the number of species, the higher the diversity and vice versa.

<em>Adjacent development close to the pond can be viewed as habitat disturbance. Habitat disturbance affects biodiversity in a number of ways including:</em>

  • <em>A shift in the species composition of the habitat</em>
  • <em>Outright extinction of certain species from the population</em>

<em>Overall, the species diversity become reduced as a result of a shift in species composition of extinction of some species. Hence, the best indicator of habitat disturbance is a decrease in biodiversity of the habitat.</em>

The correct option is e.

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3 years ago
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Natasha2012 [34]

Answer:

a

Explanation:

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Jamie is a top-level gymnast. As a gymnast, Jamie has good balance and coordination of movement. The area of Jamie's brain that
saul85 [17]

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The cerebellum.

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5 0
3 years ago
In a tropical forest there is a species of bird that has a variable tail length. Long is incompletely dominant over short. In on
Temka [501]

Answer:

Frequency of long trait allele = 0.55

Frequency of long trait allele = 0.45

Explanation:

Given -

Total Number of birds  - 2000

Let us assume the given population is in Hardy Weinberg's equation -

Frequency of individuals with birds having long tails is depicted by p^2

Frequency of individuals with birds having short tails is depicted by q^2

Frequency of individuals with birds having medium tails is depicted by 2pq

Frequency of individuals with birds having long tails

\frac{614}{2000} * 100\\= 30.7

p^2 = .307\\p = 0.554

Frequency of individuals with birds having short tails

\frac{413}{2000} *100\\20.65

q^ 2 = 0.2065\\q = 0.4544

Rounding off the values of p and q we get

Frequency of long trait allele = 0.55

Frequency of long trait allele = 0.45

Sum of both  p and q should be unity

0.55+ 0.45 = 1

6 0
4 years ago
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