He should have added 1 to both sides to make the -1 on the right go to 0.
Then it would be 0 + m = -16 + 1 = -15
You can check your work by adding -1 and -15, which does in fact equal -16.
Hope this helped :)
Answer:
The general solution of the equation is y =
+ 5
Step-by-step explanation:
Since the differential equation is given as y'(t) = 3y -5
The differential equation is re-written as
dy/dt = 3y - 5
separating the variables, we have
dy/(3y - 5) = dt
dy/(3y - 5) = dt
integrating both sides, we have
∫dy/(3y - 5) = ∫dt
∫3dy/[3(3y - 5)] = ∫dt
(1/3)∫3dy/(3y - 5) = ∫dt
(1/3)㏑(3y - 5) = t + C
㏑(3y - 5) = 3t + 3C
taking exponents of both sides, we have
exp[㏑(3y - 5)] = exp(3t + 3C)
3y - 5 =
3y - 5 =

3y =
+ 5
dividing through by 3, we have
y =
+ 5
So, the general solution of the equation is y =
+ 5
Answer:
y = 16 
Step-by-step explanation:
Use the given points to find the values of a and b
Using (0, 16), then
16 = a
(
= 1 ), thus
a = 16
y = 16 
Using (2, 400), then
400 = 16b² ( divide both sides by 16 )
b² = 25 ( take the square root of both sides )
b =
= 5
Thus
y = 16 ×
← exponential function