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nikklg [1K]
3 years ago
9

Find the slope of the line passing through these points: (5,2) and (-10,12)

Mathematics
1 answer:
Marat540 [252]3 years ago
3 0

Answer:

-2/3

Step-by-step explanation:

The slope of a line is found by

m= (y2-y1)/(x2-x1)

   = (12-2)/(-10 -5)

   = 10/-15

    = -2/3

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I have to write the slope and equation of each line pictured in y = mx + b form.
Brut [27]

Answer:

y=7/3x+8

Step-by-step explanation:

You have to start at the 3and rise all the way to the 8 which is 7 and then run which is 3 so the slope mx is 7/3x. To find b which is the y intercept find the point where the line hits the y-axis.

5 0
3 years ago
Evaluate this expression |-9|
N76 [4]

Answer:9

Step-by-step explanation:

The distance between-9 and 0 is 9.

3 0
3 years ago
Read 2 more answers
The product of a constant factor 15 and a 2-term factor x+4
dezoksy [38]
The product of 15 and x+4 is 15(x+4) = 15x+60. This is a linear binomial.

4x^3-2x-9-(2x^3) is a cubic trinomial. In your original question, I'm not sure what the 5x+3 means.
6 0
3 years ago
HELP!!! Use the factor Theorem to determine whether the binomial x+1 is a factor of the polynomial function f(x) =2x^3-9x^2+13x-
Dovator [93]

ANSWER

A. No because f(c)=-30

EXPLANATION

The given polynomial is

f(x) =2x^3-9x^2+13x-6

If x+1 is a factor , then f(-1) must evaluate to zero.

f( - 1) =2( - 1)^3-9( - 1)^2+13( - 1)-6

f( - 1) =2( - 1)-9( 1)+13( - 1)-6

f( - 1) = - 2-9 - 13-6

f( - 1) = -11 - 19

f( - 1) = - 30

Since f(-1) is not equal to zero, x+1 is not a factor of

f(x) =2x^3-9x^2+13x-6

6 0
3 years ago
Solve the equation on the interval [0,2π). 7 sec x-7=0, x=?
Oksanka [162]

\huge \bf༆ Answer ༄

Let's solve ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:7 \sec(x)  - 7 = 0

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:7 \sec(x)  = 7

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sec(x)  = 7 \div 7

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \sec(x)  = 1

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 0

8 0
2 years ago
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