All categories

3 years ago

A car dealer sells a car for $42000 which represent a 25% profit over the cost. What was the cost of car to the dealer

Mathematics

1 answer:

Olin [163]3 years ago

4 0

Answer:

$33600

Step-by-step explanation:

Let x = original car price

Since it is a 25% profit that means we multiply x by 1.25

1.25x = 42000

Divide both sides by 1.25

1.25x/1.25 = 42000/1.25

x = 33600

You might be interested in

Please dont ignore, Need help!!! Use the law of sines/cosines to find..

Ket [755]

Answer:

16. Angle C is approximately 13.0 degrees.

17. The length of segment BC is approximately 45.0.

18. Angle B is approximately 26.0 degrees.

15. The length of segment DF "e" is approximately 12.9.

Step-by-step explanation:

By the law of sine, the sine of interior angles of a triangle are proportional to the length of the side opposite to that angle.

For triangle ABC:

$\sin{A} = \sin{103\textdegree{}}$ ,
The opposite side of angle A $a = BC = 26$ ,
The angle C is to be found, and
The length of the side opposite to angle C $c = AB = 6$ .

$\displaystyle \frac{\sin{C}}{\sin{A}} = \frac{c}{a}$ .

$\displaystyle \sin{C} = \frac{c}{a}\cdot \sin{A} = \frac{6}{26}\times \sin{103\textdegree}$ .

$\displaystyle C = \sin^{-1}{(\sin{C}}) = \sin^{-1}{\left(\frac{c}{a}\cdot \sin{A}\right)} = \sin^{-1}{\left(\frac{6}{26}\times \sin{103\textdegree}}\right)} = 13.0\textdegree{}$ .

Note that the inverse sine function here $\sin^{-1}()$ is also known as arcsin.

By the law of cosine,

$c^{2} = a^{2} + b^{2} - 2\;a\cdot b\cdot \cos{C}$ ,

where

$a$ , $b$ , and $c$ are the lengths of sides of triangle ABC, and
$\cos{C}$ is the cosine of angle C.

For triangle ABC:

$b = 21$ ,
$c = 30$ ,
The length of $a$ (segment BC) is to be found, and
The cosine of angle A is $\cos{123\textdegree}$ .

Therefore, replace C in the equation with A, and the law of cosine will become:

$a^{2} = b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}$ .

$\displaystyle \begin{aligned}a &= \sqrt{b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}}\\&=\sqrt{21^{2} + 30^{2} - 2\times 21\times 30 \times \cos{123\textdegree}}\\&=45.0 \end{aligned}$ .

For triangle ABC:

$a = 14$ ,
$b = 9$ ,
$c = 6$ , and
Angle B is to be found.

Start by finding the cosine of angle B. Apply the law of cosine.

$b^{2} = a^{2} + c^{2} - 2\;a\cdot c\cdot \cos{B}$ .

$\displaystyle \cos{B} = \frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}$ .

$\displaystyle B = \cos^{-1}{\left(\frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}\right)} = \cos^{-1}{\left(\frac{14^{2} + 6^{2} - 9^{2}}{2\times 14\times 6}\right)} = 26.0\textdegree$ .

For triangle DEF:

The length of segment DF is to be found,
The length of segment EF is 9,
The sine of angle E is $\sin{64\textdegree}}$ , and
The sine of angle D is $\sin{39\textdegree}$ .

Apply the law of sine:

$\displaystyle \frac{DF}{EF} = \frac{\sin{E}}{\sin{D}}$

$\displaystyle DF = \frac{\sin{E}}{\sin{D}}\cdot EF = \frac{\sin{64\textdegree}}{39\textdegree} \times 9 = 12.9$ .

7 0

3 years ago

For geometry:(<br><br> will give brainist

Tasya [4]

Answer:

Clearly show i can't see ur answer

7 0

3 years ago

Read 2 more answers

Someone please help me !!!! Will mark Brianliest !!!!!!!!!!!!!!!!

BARSIC [14]

Answer:

once again try -4+1

hope it helps

5 0

3 years ago

Rename 600,000= ten thousands

lyudmila [28]

For this case we have the following number:

600,000

We can rewrite this number as the product of two numbers.

We have then, mathematically:

600,000 = 60 * 10,000

Then, rewriting in words we have:

600,000 = sixty - ten thousand s

Answer:

Rewriting 600,000 we have:

600,000 = sixty - ten thousands

4 0

3 years ago

Read 2 more answers

Greg rented a truck for one day there was a base fee of $16.99 and there was additional charge of $.89 for each mile driven Greg

julia-pushkina [17]

Let m represent the number of mile Greg drove. His rental charge was
207.45 = 16.99 + 0.89m
Subtract 16.99 and divide by 0.89
190.46 = 0.89 m
214 = m

Greg drove the truck 214 miles.

7 0

3 years ago