The notation V(r) actually gives the volume of air inside the basketball. V(r) is volume as a function of radius, r It can be written as: V(r) = 4/3πr³ So, for any value of r, we can get the volume V. For, example, when r = 7cm we can say; V(7) = 4/3 x 22/7 x 7³ = 1437.33 cm³
Hi!
You can find the value of x by the fact that as triangle CBE and CKE are congruent. The reason you can see the triangles are congruent is because of the AAS congruence postulate, where if two angles are the same and a non included side are congruent, the triangles are similar. In this case, angle CKE and angle CBE, are congruent, and CEB and CEK are congruent as well. (They're marked out as congruent.) The line CE is congruent to the other CE in the other triangle, because they are the same line.
Since you know the triangles are congruent, according to CPCTC (corresponding parts in congruent triangles are congruent), and line CK is congruent to line CB, line CK is congruent to CB, and has the same measure.
Therefore, you can set the measures of CB (5x - 3) and CK (3x + 1) equal to another and solve for x.
5x - 3 = 3x + 1
5x -3 + 3 = 3x + 1 + 3
5x = 3x + 4
5x - 3x = 3x - 3x + 4
2x = 4
2x / 2 = 4/2
x = 2, or choice C.
Hope this helps!
Answer:
Normally Distributed.
Explanation:
After plugging all those numbers into a calculator you can see that the graph isn't left skewed, making both "left skewed" and "all of the above" <em>not an answer.</em> "correlated with a second set of data" is also <em>wrong</em> since there was no second set of data given. That leaves you between "uniformly distributed" and "normally distributed" This graph doesn't show a uniformly distributed graph, which leaves you with the final answer, normally distributed.
APEX
Answer:
J: (-4,5)
K: (-4,4)
L: (-5,4)
K: (-6,6)
Step-by-step explanation:
C is the one that multiplies to a negative number because
A multiples to positive 1
B also multpilies to positive 1 and d multiples to 0
A negative multiplied by a negative is a positive
A netative multiplied by a positive is a negative