Answer:
Yes, Rolle's theorem can be applied
There is only one value of c such that f'(c) = 0, and this is c = 1.5 (or 3/2 in fraction form)
Step-by-step explanation:
Yes, Rolle's theorem can be applied on this function because the function is continuous in the closed interval (it is a polynomial function) and differentiable in the open interval, and f(a) = f(b) given that:
Then there must be a c in the open interval for which f'(c) =0
In order to find "c", we derive the function and evaluate it at "c", making the derivative equal zero, to solve for c:
There is a unique answer for c, and that is c = 1.5
Answer: Choice A) 12x^2 - 48x + 21; all real numbers
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Work Shown:
(f * g)(x) = f(x) * g(x)
(f * g)(x) = ( f(x) ) * ( g(x) )
(f * g)(x) = ( -2x+7 ) * ( -6x+3 )
(f * g)(x) = -2x*( -6x+3 ) + 7*( -6x+3 )
(f * g)(x) = -2x*(-6x) - 2x*(3) + 7*(-6x) + 7*(3)
(f * g)(x) = 12x^2 - 6x - 42x + 21
(f * g)(x) = 12x^2 - 48x + 21
The domain is the set of all real numbers because we can plug in any number in for x, to get some output for y. There are no issues to worry about such as division by zero errors, square root of a negative number, etc.
Answer:
t = [0.493,4.2]
Step-by-step explanation:
The height of the rocket straight up into the air is given by :
We need to find the interval the rocket be at least 43 feet above the ground.
So, the required interval during which the rocket is at least 43 feet above the ground is [0.493,4.2].
Answer:
3/4 x 2/2= 6/8
Step-by-step explanation:
multiply 3/4 x 2/2 to equal = 6/8
