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Sergio039 [100]
3 years ago
6

In the ground state, which atom has a completely filled valence electron shell?

Chemistry
1 answer:
Elina [12.6K]3 years ago
4 0

Answer:

The noble gases(neon, helium, argon)

Explanation:

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The inside window pane in your house feels very cold to touch on a winter night. How does the heat transfer?
kondaur [170]

Answer:

its B

Explanation:

Because its can only go cold to hot. -hope this help :)

4 0
3 years ago
Which formula equation represents the burning of sulfur to produce sulfur dioxide?
Dmitriy789 [7]

Answer:

option A = S(s) + O₂(g)   →   SO₂ (s)

Explanation:

Chemical equation:

S(s) + O₂(g)   →   SO₂ (s)

when sulfur burned in the presence of oxygen it produce sulfur dioxide. The sulfur dioxide can further react with oxygen to produce sulfur trioxide and then react with water to form sulfuric acid.

Uses of sulfur dioxde:

It is used as a solvent and reagent in laboratory.

Sulfur dioxide is used to produce sulfuric acid.

It is used as a disinfectant

It is also used as a reducing agent.

It is used to preserve the dry food.

7 0
3 years ago
Select all of the answers that apply.
shtirl [24]
The odysseyware answer is the same as his wood manure and food crops
5 0
3 years ago
Read 2 more answers
Question 8<br>Which one of the following salts does not contain water of crystallisation?​
BlackZzzverrR [31]
Baking soda is sodium bicarbonate in anhydrous form without any water of crystallisation and it is widely used as dry fire extinguisher because of its alkali nature.
7 0
2 years ago
Read 2 more answers
A 5-kg quantity of radioactive isotope decays to 2 kg after 10 years. Find the decay constant of the isotope.k = _____
Dvinal [7]

Answer:

k = -0.09165 years^(-1)

Explanation:

The exponential decay model of a radioactive isotope is generally given as;

A(t) = A_o(e^(kt))

Where;

A_o is quantity of isotope before decay, k is decay constant and A(t) is quantity after t years

We are given;

A_o = 5 kg

A(10) = 2kg

t = 10 years

Thus;

A(10) = 2 = 5(e^(10k))

Thus;

2 = 5(e^(10k))

2/5 = (e^(10k))

0.4 = (e^(10k))

In 0.4 = 10k

-0.9164 = 10k

k = -0.9164/10

k = -0.09165 years^(-1)

7 0
2 years ago
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