Question

some amusement parks have a ride where people are attached to a long cable, pulled back, and let go, like a pendulum. if the cable is 45.5 m long, what will the period of oscillation be?(unit=s)

Answer 1

Answer:

The period is  $T = 13.53 \ sec$

Explanation:

From the question we are told that

     The length of the cable is  $L = 45.5 \ m$

Let take acceleration due to gravity as $g = 9.8 \ m/s^2$

Now the period of the oscillation is mathematically represented as

          $T = 2 \pi \sqrt{\frac{L}{g} }$

substituting values

          $T = 2 * 3.142 \sqrt{\frac{45.5}{9.8} }$

          $T = 13.53 \ sec$