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jolli1 [7]
3 years ago
12

The distance xm travelled by a particle in time t seconds is described by the equation x = 10 + 12tsquare, Find the average spee

d of the particle between the time interval t = 2s and t = 5s
A. 60 ms-1
B. 72 ms-1
C. 84 ms-1
D. 108 ms-1​
Physics
1 answer:
Paraphin [41]3 years ago
5 0

After 2 seconds the particle will be in position

x(2)=10+12\cdot 2^2=10+12\cdot 4=10+48=58

After 5 seconds the particle will be in position

x(5)=10+12\cdot 5^2=10+12\cdot 25=10+300=310

So, the particle will travel

310-58=252

meters in 3 seconds, for an average speed of

\dfrac{252}{3}=84

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Use Kepler’s third law and the orbital motion of Earth to determine the mass of the Sun. The average distance between Earth and
dexar [7]

Kepler’s
third law formula: T^2=4pi^2*r^3/(GM)

We’re trying to find M, so:

M=4pi^2*r^3/(G*T^2)

M=4pi^2*(1.496
× 10^11 m)^3/((6.674× 10^-11N*m^2/kg^2)*(365.26days)^2)

M=1.48× 10^40(m^3)/((N*m^2/kg^2)*days^2))

Let’s work
with the units:

(m^3)/((N*m^2/kg^2)*days^2))=

=(m^3*kg^2)/(N*m^2*days^2)

=(m*kg^2)/(N*days^2)

=(m*kg^2)/((kg*m/s^2)*days^2)

=(kg)/(days^2/s^2)

=(kg*s^2)/(days^2)

So:

M=1.48× 10^40(kg*s^2)/(days^2)

Now we need to convert days to seconds in order to cancel
them:

1 day=24 hours=24*60minutes=24*60*60s=86400s

M=1.48× 10^40(kg*s^2)/((86400s)^2)

M=1.48× 10^40(kg*s^2)/(
86400^2*s^2)

M=1.48× 10^40kg/86400^2

M=1.98x10^30kg

The
closest answer is 1.99
× 10^30

(it may vary
a little with rounding – the difference is less than 1%)


8 0
3 years ago
Read 2 more answers
Do help me pleaseeeee
Anton [14]
The mass needed at peg 1 is a 5g mass.

The 15g should hang at peg 5.

The reason is force x distance clockwise is equal to force x distance anti-clockwise
8 0
3 years ago
where the units of x are length and the numbers 2.6 and 5.1 have appropriate units so that U(x) has units of energy. What is the
KiRa [710]

Answer:

x = 1.00486 m

Explanation:

The complete question is:

" The potential energy between two atoms in a particular molecule has the form U(x) =(2.6)/x^8 −(5.1)/x^4 where the units of x are length and the num- bers 2.6 and 5.1 have appropriate units so that U(x) has units of energy. What is the equilibrium separation of the atoms (that is the distance at which the force between the atoms is zero)?  "

Solution:

- The correlation between force F and energy U is given as:

                                  F = - dU / dx

                                  F = - d[(2.6)/x^8 −(5.1)/x^4] / dx  

                                  F = 20.8 / x^9 - 20.4 / x^5

- The equilibrium separation distance between atoms is given when Force F is zero:

                                  0 = 20.8 / x^9 - 20.4 / x^5

                                  0 = 20.8 - 20.4*x^4

                                  x^4 = 20.8/20.4

                                  x = ( 20.8/20.4 )^0.25

                                  x = 1.00486 m

5 0
3 years ago
A 10.00-kilogram block slides along a horizontal, frictionless surface at 12.0 meters per second for 6.00 seconds. The magnitude
earnstyle [38]

Answer:

120 kg m/s

Explanation:

The magnitude of the momentum of an object is given by

p=mv

where

m is the mass of the object

v is its speed

For the block in this problem,

m = 10.0 kg (mass of the block)

v = 12.0 m/s (speed of the block)

Therefore the magnitude of the block's momentum is

p=(10.0 kg)(12.0 m/s)=120 kg m/s

4 0
3 years ago
The image is the question
Evgen [1.6K]

Answer:

c is the answer because it i in a series not a parallel circut.

Explanation:

3 0
4 years ago
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