One point will be X1,Y1 and the other will be X2,Y2. It does not matter which is which except that X1 and Y1 have to be the same point and X2 and Y2 have to be the same point. For example, let's say you were given (2,3) and (6,8). No matter which point is X1,Y1 and the other is X2,Y2, the slope will still be 5/4.
The rise is the change in y from one point to the other. The run would be the change in x from one point to the other.
On the ball, there is mg of net force.
<h3>How would one describe air resistance?</h3>
- Air exerts a force known as air resistance. The force works in the opposite direction of an object traveling through the air.
- While a sports vehicle with a streamlined design will encounter reduced air resistance and experience less drag, the automobile will be able to move more quickly than a truck with a flat front.
<h3>What Causes Air Resistance?</h3>
- Air resistance, also referred to as "drag," is a force brought on by air. When air specks collide with an object's front, it slows down.
- The more air particles that impact the object and the larger its surface area, the more resistance it faces.
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Answer:
The net acceleration of the boat is approximately 6.12 m/s² downwards
Explanation:
The buoyant or lifting force applied to the boat = 790 N
The mass of the boat lifted by the buoyant force = 214 kg
The force applied to a body is defined as the product of the mass and the acceleration of the body. Therefore, the buoyant force, F, acting on the boat can be presented as follows;
Fₐ = F - W
The weight of the boat = 214 × 9.81 = 2099.34 N
Therefore;
Fₐ = 790 - 2099.34 = -1309.34 N
Fₐ = Mass of the boat × The acceleration of the boat
Given that the buoyant force, Fₐ, is the net force acting on the boat, we have;
F = Mass of the boat × The net acceleration of the boat
F = -1309.34 N = 214 kg × The net acceleration of the boat
∴ The net acceleration of the boat = -1309.34 N/(214 kg) ≈ -6.12 m/s²
The net acceleration of the boat ≈ 6.12 m/s² downwards
You must throw the snow ball by velocity 9.43 m/s horizontally to
hit him
Explanation:
You throw the snow ball horizontally from a height 5.5 meters
Your favorite physics teacher is 10 m away from you
You hit him on the foot
1. The initial velocity of the ball is v
2. The vertical component of v is zero because you throw the ball
horizontally
3. The vertical distance h is 5.5 m
4. The horizontal distance x is 10 m
We need to find how fast you must throw the snow ball to hit him
→ h = 
t + 
g t²
→ h = -5.5 m ⇒ height below the point of thrown
→ g = -9.8 m/s²
→ = 0 ⇒ vertical component of v
→ -5.5 = (0) t + (-9.8) t²
→ - 5.5 = -4.9 t²
Divide both sides by -4.9
→ t² = 1.12245
Take √ for both sides
→ t = 1.06 seconds
→ x = 
t
→ = v
→ x = 10 m , t = 1.06
→ 10 = v(1.06)
Divide both sides by 1.06
→ v = 9.43 m/s
You must throw the snow ball by velocity 9.43 m/s horizontally to
hit him
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