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2 years ago

Earning Goal: To be able to calculate work done by a constant force directed at different angles relative to displacement

Physics

1 answer:

lana [24]2 years ago

8 0

Answer:

the work done by the 30N force is 4156.92 J.

For this problem, they don´t ask you to determine the work of the total force applied in the block. They only want the work done for the force of 30N, with an angle of 30º respectively of the displacement and a traveled distance of 160m. So:

W=F·s·cos(α)=30N·160m·cos(30º)=4156.92J

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2 years ago

Read 2 more answers

Below are three graphs. The shape of graph 3 shows that the current flowing through this component is __________ proportional to

dalvyx [7]

The relationship between variables might be either directly porportional to each other or inversely proportional to each other. <em>For instance, the current flowing is _</em><em><u>directly</u></em><em>_ </em><em>proportional to the potential difference across</em> it.

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Since I do not have the graph, I will propose two potential options and I will describe each of them.

I suggest you to choose the one that matches the shape of graph 3.

<h3>Graphs</h3>

Probably your graph is composed of the X and Y axes, perpendicularly placed, in a way in which four quadrants are formed.

You might see that one of the axes represents the current (I), and the other one represents the potential difference (V).

And a straight line that represents the relationship between the current and the potential difference.

The direction of the straight line reflects the relationship between variables.

The change on each variable is proportional to the change on the other variable. Now we have to analyze how that change occurs.

<h3 /><h3>Option 1 </h3>

<em>The current flowing through this component is __</em><u><em>DIRECTLY</em></u><em>__ proportional to the potential difference across it</em>.

If this is the case of your graph, you should see the straight line crossing from the left inferior quadrant to the right superior one.

The direction of the line suggests that one of the variables increases as the other one increases too. <em>The current increases as the potential increases. </em>

<h3 /><h3 /><h3>Option 2 </h3>

<em>The current flowing through this component is __</em><u><em>INVERSELY</em></u><u><em>_</em></u><em>_ proportional to the potential difference across it.</em>

If this is the case of your graph, you should see the straight line crossing the right quadrant from the superior left corner to the inferior right one.

The direction of the line suggests that the variable represented in the Y ax decreases as the other one increases.

For instance, The current decreases as the potential increases. Or the potential decreases as the current increases.

In the attached files you will find graphs of both options.

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You can learn more about the Ohm's law at

brainly.com/question/17286882?referrer=searchResults

You can learn more about the relationship between variables at

brainly.com/question/16937826?referrer=searchResults

brainly.com/question/21627823?referrer=searchResults

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2 years ago

The rate of spin of a disk is decreasing. A point on the disk that is near the rim of the disk will have...

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At a point near the rim of the disk, it will have a<span> non-zero radial acceleration and a zero tangential acceleration. Also known as centripetal acceleration, radial acceleration takes place along the radius of the disk. On the other hand, the tangential acceleration is along the path of disk's motion.</span>

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2 years ago

You travel an an average speed of 20 km/h in a straight line to get to your grandmothers house. It takes you 3 hours to get to h

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20km every 1 hr is what 20km/hr means.

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3 years ago

A camera lens focuses on an object 75.0 cm from the lensThe image forms 3.50 cm behind the lens. What is the magnification of th

N76 [4]

Answer:

7/150

Explanation:

The following data were obtained from the question:

Object distance (u) = 75cm

Image distance (v) = 3.5cm

Magnification (M) =..?

Magnification is simply defined as:

Magnification (M) = Image distance (v)/ object distance (u)

M = v /u

With the above formula, we can obtain the magnification of the image as follow:

M = v/u

M = 3.5/75

M = 7/150

Therefore, the magnification of the image is 7/150.

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3 years ago