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Ede4ka [16]
3 years ago
5

Earning Goal: To be able to calculate work done by a constant force directed at different angles relative to displacement

Physics
1 answer:
lana [24]3 years ago
8 0

Answer:

the work done by the 30N force is 4156.92 J.

For this problem, they don´t ask you to determine the work of the total force applied in the block. They only want the work done for the force of 30N, with an angle of 30º respectively of the displacement and a traveled distance of 160m. So:

W=F·s·cos(α)=30N·160m·cos(30º)=4156.92J

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Which states the purpose of an experiment?
Whitepunk [10]
B; to produce a hypothesis.

6 0
3 years ago
Read 2 more answers
A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axi
NeX [460]

Answer:

h = 2.087 m

Explanation:

Given

m₁ = 3 kg

v₁ = 20 m/s

m₂ = 2 kg

v₂ = - 14 m/s

In a completely inelastic collision the colliding objects stick together after the collision and move together as a single object.

In the given problem, lets assume that the balls of putty are initially moving along the  y  axis, upward direction being the positive  y  direction. And the collision occurs at the origin of the coordinate system.

We can apply the equation

vs = (m₁*v₁ + m₂*v₂) / (m₁ + m₂)  

⇒   vs = (3 kg*20 m/s + 2 kg*(- 14 m/s)) / (3 kg + 2 kg)  

⇒   vs = 6.4 m/s (↑)

To calculate the maximum height  h  attained by the combined system of two balls of putty after the the collision, we use the expression for linear motion under gravity:

vf² = vi² - 2*g*h

where

vf = 0 m/s  

g = 9.81 m/s²

vi = vs = 6.4 m/s

finally we get h:

h = vi² / (2*g)

⇒   h = (6.4 m/s)² / (2*9.81 m/s²) = 2.087 m

6 0
3 years ago
A hollow conducting sphere with an outer radius of 0.295 m and an inner radius of 0.200 m has a uniform surface charge density o
IrinaK [193]

Answer:

a. 6.032\times10^{-6}C/m^2

b.6.816\times10^5N/C

Explanation:

#Apply  surface charge density, electric field, and Gauss law to solve:

a. Surface charge density is defined as charge per area denoted as \sigma

\sigma=\frac{Q}{4\pi r_{out}^2}, and the strength of the electric field outside the sphere E=\frac{\sigma _{new}}{\epsilon _o}

Using Gauss Law, total electric flux out of a closed surface is equal to the total charge enclosed divided by the permittivity.

\phi=\frac{Q_{enclosed}}{\epsilon_o}\\\\\sigma=\frac{Q}{4\pi r_{out}^2}\\\\\sigma=\frac{0.370\times 10^{-6}}{4\pi \times (0.295m)^2}\\\\=3.383\times10^{-7}C/m^2  #surface charge outside sphere.

\sigma_{new}=\sigma_{s}-\sigma\\\\\sigma_{new}=6.37\times10^{-6}C/m^2-3.383\times10^{-7}C/m^2\\\\\sigma_{new}=6.032\times10^{-6}C/m^2

Hence, the new charge density on the outside of the sphere is 6.032\times10^{-6}C/m^2

b. The strength of the electric field just outside the sphere is calculated as:

From a above, we know the new surface charge to be 6.032\times10^{-6}C/m^2,

E=\frac{\sigma _{new}}{\epsilon _o}\\\\=\frac{6.032\times10^{-6}C/m^2}{\epsilon _o}\\\\\epsilon _o=8.85\times10^{-12}C^2/N.m^2\\\\E=\frac{6.032\times10^{-6}C/m^2}{8.85\times10^{-12}C^2/N.m^2}\\\\E=6.816\times10^5N/C

Hence, the strength of the electric field just outside the sphere is 6.816\times10^5N/C

5 0
3 years ago
1) ________ is a force that you can fell with your feet
Kay [80]

Answer:

1. Weight

2. potassium chlorate

3. pushing forward

Explanation:

1. Our full body stands in our feet, so feet takes all the weight of the body. In Newtonian mechanics, weight is a force. Weight is happened with the interaction between the mass and gravitational field. As the gravitational field is a vector, it has directions that are downward. So the interaction between mass and gravitational field works downward. So all the weight is felt by our feet.

2. In a fire stick, potassium chlorate is used. Potassium is known as a flammable chemical. Potassium chlorate is used in the upper part of the fire stick. When potassium chlorate faces frictions, a chemical reaction is happened, which creates great heat. The heat makes extra oxygen and heat, which makes the stick burn and create fire.

3. It is easy to rolling than push forward. If we consider a heavy lawn roller, the weight of the roller works downward. If we push the lawn roller, the force divided into two sub forces. One works downward which increases the weight of the roller and other works forward. But if we roll the lawn roller, the forces divided into two forces: upward and forward. Upward force makes the weight decrease and forward force makes it move forward. As the weight decrease, it becomes easy to roll than push

3 0
3 years ago
A car changes speed from 25 m/s to 10 m/s in 240 seconds. Describe its acceleration.​
Dmitry_Shevchenko [17]

Explanation:

Acceleration is change in velocity over change in time:

a = Δv / Δt

a = (10 m/s - 25 m/s) / (240 s - 0 s)

a = -0.0625 m/s²

So the car decelerates at 0.0625 m/s².

7 0
4 years ago
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