PHYSICS HELP<br><br>I got the 1st 2.

An arteriole has a radius of 25 μm and it is 1000 μm long. The viscosity of blood is 3 x 10-3 Pa s and its density is 1.055 g cm

timama [110]

Answer: $1.955(10)^{13} \frac{Pa.s}{m^{3}}$

Explanation:

This can be solved by the Poiseuille’s law for a laminar flow:

$R=\frac{8 \eta L}{\pi r^{4}}$

Where:

$R$ is the resistance of the arteriole

$\eta=3(10)^{-3} Pa.s$ is the viscosity of blood

$L=1000 \mu m=1000(10)^{-6}m$ is the length of the arteriole

$r=25 \mu m=25(10)^{-6}m$ is the radius of the arteriole

$R=\frac{8 (3(10)^{-3} Pa.s)(1000(10)^{-6}m)}{\pi (25(10)^{-6}m)^{4}}$

$R=1.955(10)^{13} \frac{Pa.s}{m^{3}}$

3 0

4 years ago

Consider the following hypotheses: 12:V ) >(x)) Use rules of inference to prove that the following conclusion follows from th

Igoryamba

Answer: See attachment below

Explanation:

8 0

3 years ago

Direct current, DC, flows in a _________ direction while alternating current, AC, the direction of flow ___________. A) single,

kramer

The flow of Direct current (DC) is constant and flows in one direction. Most digital electronics make use of DC. Alternating current (AC) periodically flows in reverse and is mostly used to deliver power to houses, buildings and the like. With that alone, you can already rule out A, C and D.

The answer would then be B. constant, periodically reversing.

4 0

4 years ago

Read 2 more answers

The power dissipated in a resistor is given by P = V 2 / R , which means power decreases if resistance increases. Yet this power

klasskru [66]

Answer:

Explanation:

Power Dissipated in a resistor is given by two methods i.e.

$P=\frac{V^2}{R}$ and

$P=I^2\cdot R$

where $V=Potential\ difference$

$R=resistor$

$I=current$

both formula gives Power but Former is used when voltage is constant i.e. when resistors are in parallel and the later is used when the resistor are in series .

Though $P=\frac{V^2}{R}$ can also be used in series but we have to calculate the Potential drop across each resistor then we can apply the formula.

Similar is with $P=I^2R$

First we have to calculate current through each resistor then we can apply the Formula

5 0

3 years ago

An inverted image of an object is viewed on a screen from the side facing a converging lens. An opaque card is then introduced c

Marta_Voda [28]

Answer:

d) The image would be dimmer

Explanation:

When inverted image of an object is viewed on a screen from the side facing a converging lens, the

lens focuses the diverging, and blurred light rays from the distance object through refraction of the rays two times.Then the rays is converge by the double bending cl at a focal point behind the lens inorder for a sharper image to be be observed.

But when an opaque card is then introduced to cover only the upper half of the lens then the image becomes dimmer because of the reduction in the light intensity on the screen by 50%

5 0

3 years ago

PHYSICS HELPI got the 1st 2.​

PHYSICS HELPI got the 1st 2.