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3 years ago

Match the function with the graph.

Mathematics

2 answers:

victus00 [196]3 years ago

8 0

Answer:

A) g(x)= -(x-6)^2

Step-by-step explanation:

The graph is of a parabola, so there must be a ^2

If you plug the equation into the graphing calculator it will graph it for you.

astraxan [27]3 years ago

6 0

Can I see the graph?

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The mean number of automobiles entering a mountain tunnel per two-minute period is one. An excessive number of cars entering the

viva [34]

Answer:

A Poisson model seems reasonable for this problem, since we have the mean during the time interval.

There is a 1.9% probability that the number of autos entering the tunnel during a two-minute period exceeds three.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x)=\frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

The mean number of automobiles entering a mountain tunnel per two-minute period is one.

This means that $\mu = 1$ .

For a Poisson model to be reasonable, we only need the mean during the time interval. So yes, a Poisson model seems reasonable for this problem.

Find the probability that the number of autos entering the tunnel during a two-minute period exceeds three.

We want to find $P(X>3)$

Either this number is less or equal to 3, or it exceeds 3. The sum of the probabilities is decimal 1. So:

$P(X \leq 3) + P(X > 3) = 1$

$P(X > 3) = 1 - P(X \leq 3)$

In which

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-1}*1^{0}}{(0)!} = 0.3679$

$P(X = 1) = \frac{e^{-1}*1^{1}}{(1)!} = 0.3679$

$P(X = 2) = \frac{e^{-1}*1^{2}}{(2)!} = 0.1839$

$P(X = 3) = \frac{e^{-1}*1^{3}}{(3)!} = 0.0613$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3679 + 0.3679 + 0.1839 + 0.0613 = 0.981$

Finally

$P(X > 3) = 1 - P(X \leq 3) = 1 - 0.981 = 0.019$

There is a 1.9% probability that the number of autos entering the tunnel during a two-minute period exceeds three.

8 0

3 years ago

What is the product written in scientific notation?

Lesechka [4]

$(2.6*x^{-4})*(2.2*x^{8}) = (2.6*2.2)*(x^{-4} * x^{8})=(5.72)*(x^{-4+8})= \\ =5.72*x^{4}

$

8 0

3 years ago

: A recruiter travels 1,100 miles during a 40–hour workweek. If she spends 2⁄5 of her time traveling, how many hours does she sp

s2008m [1.1K]

She spends 16 hours traveling.

Hope this helped! If it did please Mark as Brainliest! ;) Thanks!

5 0

3 years ago

PLEASE HELP ME!

Anuta_ua [19.1K]

3.7 e+7 = <em>37,000,000.</em>

" e+7 " means "move the decimal point 7 places
making it bigger". (to the right)

" e-5 " would mean "move the decimal point 5 places
making it smaller". (to the left)

4 0

3 years ago

Solve and check the inequality<br> |8m+4|<12

alexgriva [62]

This is the concept of algebra, to solve the inequality we proceed as follows;
|8m+4|<12
given that the absolute value is represented by positive and negative values, we shall have:
-(8m+4)<12
-8m-4<12
-8m<12+4
-8m<16
thus;
m>16/(-8)
m>-2

also:
8m+4<12
8m<12-4
8m<8
m<8/8
m<1
hence the answer is -2<m<1

7 0

3 years ago