Answer:
Width of the pool = 15 yards
Step-by-step explanation:
Given that:
Length of diagonal of swimming pool = 29 yards
Length of the pool = 25 yards
Let,
w be the width.
This will form a right angled triangle where the diagonal will be hypotenuse.
Using Pythagorean theorem;

Taking square root on both sides

Rounding off to nearest whole number
w = 15 yards
Hence,
Width of the pool = 15 yards
Answer:
(-2.2, -1.6), (3, 1)
Step-by-step explanation:
You don't have to go far to find the equations. They are right there in your problem statement. Perhaps you want to find the solutions to the equations.
Use the first equation to write an expression for x, then substitute that into the second equation:
x = 2y +1
y^2 -3(2y+1)(y) +8 = 0
-5y^2 -3y +8 = 0
-(5y +8)(y -1) = 0
y = -8/5 or y = 1
The corresponding values of x are ...
x = 2(-8/5)+1 = -11/5
x = 2(1) +1 = 3
The solutions are (x, y) = (-2.2, -1.6) and (3, 1).
Answer:
255
Step-by-step explanation:
(1-15%)a=300
a=255
Answer:
the base is 10 and the height is 6.4
This problem cannot be solved unless we are given figure NPQR is a rhombus.
In that case, then all sides are equal, meaning
5x+16=9x-32
Solve for x
9x-5x=16+32
4x=48
x=12
Each side (including PQ) then equals 5x+16=5*12+16=76