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AleksAgata [21]
3 years ago
5

If you change the sign of a point's x-coordinate, how does the location of the point change? CLEAR CHECK The point moves down an

d to the left. The point crosses over the x-axis. The point crosses over the y-axis. Not enough information is provided.
Mathematics
1 answer:
Fudgin [204]3 years ago
4 0

Answer:

The point crosses over the y-axis

Step-by-step explanation:

Given

A change in the sign of x coordinate

Required

The effect on the point location

Assume the coordinate to be (x,y).

The above point is located in the first quadrant,

When the x value changes to negative i.e. (-x,y)

The point moves from the first quadrant to the second quadrant

This implies that, the point crosses over the y-axis.

Similarly, assume the coordinate to be (-x,-y).

The above point is located in the third quadrant,

When the x value changes i.e. (x,-y)

The point moves from the first quadrant to the fourth quadrant

This implies that, the point crosses over the y-axis.

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
Based on the extreme value theorem, what is the maximum value of f(x) = –x2 + 6x over the interval [1, 4]?
Tju [1.3M]

Answer:

Maximum\ value\ =9 ,at\ x=3

Step-by-step explanation:

From the question we are told that:

Function given

f(x) = -x^2 + 6x

Co-ordinates

(x,y)=[1, 4]

Generally the second differentiation of function is mathematically given by

-2x+6

Therefore critical point

x=3

Generally the substitutions of co-ordinate into function is mathematically given by

For 1

F(1)=-(1)^2 + 6(1)\\F(1)=5

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F(4)=-(4)^2 + 6(4)\\F(4)=8

For critical point 3

F(3)=-(3)^2 + 6(3)\\F(3)=9

Therefore the maximum value of f(x) = –x2 + 6x over the interval [1, 4] is given by

Maximum\ value\ =9 ,at\ x=3

3 0
3 years ago
Read 2 more answers
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