Question

What is the radius of a circle with a center at (3,2) and a point on the circle at (9,2)

Answer 1

Answer:

-The result for the radius:

$6 = r$

-The result for the equation of a circle:

$(x-3)^2+(y-2)^2=36$

Step-by-step explanation:

The equation of a circle is:

$(x-h)^2+(y-k)^2=r^2$ where the center is represented as $(h,k)$, the point is known as $(x,y)$, and the radius  is represented as $r$ .

-Use the center (3,2) and the point (9,2) for the equation:

$(9-3)^2+(2-2)^2=r^2$

-Then, solve the equation to find the radius:

$(9-3)^2+(2-2)^2=r^2$

$(6)^2+0=r^2$

$36 =r^2$

$\sqrt{36} = \sqrt{r^2}$

$6 =r$

So, the radius is 6.