Plz help will mark as brainliest

Halle la ecuación del eje x y la ecuación del eje y, usando dos puntos que se encuentren sobre los mismos.

lisov135 [29]

Una linea recta ( cualquier eje coordenado es una línea recta) queda definida si se conocen dos puntos que están sobre ella.

Solución:

Ecuación del eje x y = 0

Ecuación del eje y x = 0

Para darle respuesta a la pregunta podemos seguir el siguiente procedimiento:

Escogemos dos puntos arbitrarios sobre el eje x, por ejemplo

P ( 2 ; 0 ) y Q ( 5 ; 0 ) ( todos los puntos sobre el eje x tienen coordenada y = 0.

Según la cual m = (y₂ - y₁)/ ( x₂ - x₁ ) m = 0

Usamos la ecuación pendiente-Intercepto

y = m×x + b donde m es la pendiente y b el intercepto con el eje y

y entonces tenemos:

m = 0 b ( 0 ; 0 )
Por sustitución en la ecuación pendiente-intercepto

y = 0

Procediendo de forma similar obtendremos la ecuación del eje y

P´( 0 ; 4 ) Q´( 0 : 8 ) entonces

y = m×x + b

En este caso, la pendiente no es definida ( tang 90° ) y b es de nuevo el punto b ( 0 ; 0).

A partir de que todos y cada uno de los puntos sobre el eje y son de valor 0 para x, concluímos que ecuación del eje y es

x = 0

Enlaces de interés:brainly.com/question/21135669?

8 0

2 years ago

If Jessica split 75 pencils between 8 people in her class and kept the leftovers, how many pencils did each classmate get?

Nataly [62]

Answer: Each classmate got 9 pencils

Step-by-step explanation: if you divide 8 from 75, you get 9 pencils for each classmate and 3 for Jessica to keep.

6 0

3 years ago

Read 2 more answers

A high school principal wishes to estimate how well his students are doing in math. Using 40 randomly chosen tests, he finds tha

ollegr [7]

Answer:

99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Step-by-step explanation:

We are given that a high school principal wishes to estimate how well his students are doing in math.

Using 40 randomly chosen tests, he finds that 77% of them received a passing grade.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students received a passing grade = 77%

n = sample of tests = 40

p = population proportion

<em>Here for constructing 99% confidence interval we have used One-sample z proportion test statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5%

level of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

<u>99% confidence interval for p</u> = [ $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.77-2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ , $0.77+2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ ]

= [0.5986 , 0.9414]

Therefore, 99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Lower bound of interval = 0.5986

Upper bound of interval = 0.9414

6 0

3 years ago

The newly elected president needs to decide the remaining 5 spots available in the cabinet he/she is appointing. If there are 15

skad [1K]

Answer: There are 360360 ways to appoint the members of the cabinet.

Step-by-step explanation:

Since we have given that

Number of eligible candidates = 15

Number of spots available = 5

We need to find the number of different ways the members can be appointed where rank matters

For this we will use "Permutations":

So, the required number of different ways in choosing the members for appointment is given by

$^{15}P_5=360360$

Hence, there are 360360 ways to appoint the members of the cabinet.

7 0

3 years ago

HELP Luna observed that in the last 12 issues of Rise Over Run Weekly, 384 of the 960 pages contained an advertisement.

Veseljchak [2.6K]

Well, 12 issues end up as 960 pages total

so... if in 960 pages, 384 are ads, what about 80 pages?

well $\bf \begin{array}{ccllll}
pages&ads\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
960&384\\
80&x
\end{array}\implies \cfrac{960}{80}=\cfrac{384}{x}$

solve for "x"

7 0

3 years ago

Read 2 more answers