Hello,
Looking at the picture you can tell that the arrows pointing to the left identify the release of thermal energy. So, we can eliminate those arrows being potential answers for this question. Next, we look at the arrows pointing to the right. Seeing as it goes from solid to a liquid to a gas, we can see that the arrows pointing to the right show the removal of thermal energy. So you should click all the arrows pointing to the right.
Hope this helps!!
Answer:
Explanation:
Sodium and potassium are present in group 1A. Both are alkali metals.
The atomic number of sodium is 11 and potassium is 19. Sodium is present in period 3rd while potassium is present in period 4th.
Electronic configuration of sodium:
Na₁₁ = 1s² 2s² 2p⁶ 3s¹
K₁₉ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹
It can be seen in electronic configuration that in case of sodium the valance electron is present in third energy level while in case of K outer most electron is present in 4th energy level. So atomic structure of sodium has three energy level and K has four energy level that's why radius of potassium is greater than sodium because its the distance from center to outer most electronic shell.
Moreover as we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.
Answer:
The answer is C for sure!
Explanation:
In the picture we have the electrons given, so we have to determine the nucleons and protons.
The strength of an acid increases if the stability of conjugate base increases
The stability of a conjugate base increases with the presence of electron with drawing group (electronegative group)
Thus more the electronegativity of an atom attached to a carboxylic acid higher the strength of acid
In these examples CH3CH2CH2CF2CH2COOH contains to electronegative flourine atoms which stabilizes the conjugate base hence this will be the strongest acid among the given acids
So, here is the reaction :
As ypu can see, oxygen is protonated and EtLi performes nucleophilic attack, the last one <span>oxidizes the carbonyl. The attachment will make it pretty clear. Good luck!</span>
