answers for vocabulary:
1) polar
2) non- polar
3)non- polar
4) polar
please ,put the questions
clearly
Answer:
Tight junctions - prevent liquid from seeping between cells
Desmosomes - act as rivets to hold adjacent cells together when epithelial tissue moves
Gap junctions - allow movement of cytosol, ions, and small molecules between animal cells
Plasmodesmata - openings through the cell walls of plant cells that allow adjacent cells to share materials
Explanation:
1) Tight junctions are one of the cell junctions found in animal cells. Tight junctions function to prevent the flow of liquid materials between cells.
2) Desmosomes are another type of cell junctions whose function is to form a connection between two adjacent cells. The structure formed by this connection confers strength upon the tissues involved.
3) Gap junctions are the most commonly found cell junctions found in animal cells that connects adjacent cells allowing the passage of cytosol, ions and other small molecules in them from one adjacent cell to another.
4) Plasmodesmata is a cell junction found in plant cells. They are small openings lying across the cell wall of plant cells whose function is to connect the cells and facilitate the movement of materials from one cell to another.
Answer:

Explanation:
Amount of water displaced by the sphere will be equal to the volume of complete sphere.
As the sphere completely sinks to the bottom of the cup.
We have been given;
Diameter of sphere (d) = 4.6 cm
So,

Volume of sphere (V):

By substituting value of r we get:

1 cm³ = 1 mL

V = 51 mL
So,
Water displaced by the sphere = 51 mL