Answer:
Let O be the center of a circle whose radius is r cm , in which AB= 14 cm long
cord is at a distanceof 24 cm from O. Draw a perpendicular OD on AB , thus ,
OD= 24 cm.
In right angled triangle. ODB
OB^2 = OD^2+ DB^2
r^2 =(24)^2+(AB/2)^2 = 576+(14/2)^2
r^2 = 576+ 49=625
r = √625. =25 cm. Answer.
Answer:
Step-by-step explanation:
32²=(40-8)²
=40²-2(40)(8)+8²
=1600-640+64
=1664-640
=1024
also 32²=1024
Answer:
h = 57.73 m
Step-by-step explanation:
We have,
The angle of elevation of the top of tower to be 30 degree
James is 100 m away horizontally from the base of the tower.
It is required to find the height of the tower.
Here, angle is 30 degree
Base, b = 100 m
Let h is the height of the tower. The relation between base and height is given by :

So, the height of the tower is 57.73 m.
You would have to find Circumference
Brown eyes because most students have brown eyes. It would be less likely to get a student with blue or green eyes.