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Mkey [24]
2 years ago
8

The Oregon Trail is 2,197 miles long. How long would it take a covered wagon traveling 20 miles a day to complete the trip? Hint

Round to the nearest
ones place
Mathematics
2 answers:
k0ka [10]2 years ago
7 0

Answer:

About 110 days

Step-by-step explanation:

Round up

2,197 would round up to 200

Divide 2,200 by 20, and there is your answer

ddd [48]2 years ago
3 0

Answer:

109 days and 9 hours

Step-by-step explanation:

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Alex drew a scale drawing of an auditorium. He used the scale 3 inches = 2 feet. If the stage is 30 inches in the drawing, how w
White raven [17]

Answer:

20 feet

Step-by-step explanation:

The scale is 3 inches is to 2 feet

As a ratio, it would be:

\dfrac{3}{2}

The question is what is the actual length of the stage if the drawing is 30 inches. All we need to do is find a ratio proportional to the scale ratio:

\dfrac{3inches}{2feet} = \dfrac{30inches}{xfeet}

Now to find the missing number, cross multiply the fractions first:

\dfrac{3}{2}=\dfrac{30}{x}

(3)(x)=(2)(30)

3x=60

Then solve for x:

3x=60

x=\dfrac{60}{3}

x=20

The answer is 20 feet

8 0
3 years ago
After a hike, a group of s students equally share 5 boxes of granola bars. Each box has 8 granola bars. Which algebraic expressi
marissa [1.9K]

Answer:

40/s

Step-by-step explanation:

Number of granola boxes = 5

Number of granola per box = 8

Total granolas = 8 * 5 = 40 granola bars

Number of students = s

If each students takes equal share : Number if granola bars taken by each :

Total number of granola bars / number of students

= 40 ÷ s

40/s

8 0
3 years ago
Four cups of flour make 5/6 batch of bread. How many cups of flour make 1 batch?
melisa1 [442]

Answer:

1 and 1/4ths a cup to make a batch if i worded that right

5 0
2 years ago
A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.
Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}

6 0
3 years ago
The radioactive element carbon-14 has half of 5750 years. A scientist determined that the bones from a mastodon has lost 56.6% o
IRISSAK [1]

Answer:7881 years

Step-by-step explanation:

You can use the equation

fraction remaining = 0.5n where n is # of half lives elapsed

n = ?

fraction remaining = 1 - 0.612 = 0.388

0.388 = 0.5n

n = 1.37 = the # of half lives

1.37 x 5750 yrs = 7881 years

8 0
3 years ago
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