Okay. In my opinion, all the class has to do is simplify the expressions and compare. But they want to substitute instead.
Well then.
First, let's notice that these are linear expressions, meaning that if they are equivalent then all their values match up.
Number 1 is not a good one. Just because they're both positive doesn't mean anything; they have to be <em>the same.</em>
This also eliminates 3.
Number 2 is a good one, but it's not as reliable. If, for instance, the two expressions are <em>not </em>equivalent and you get lucky enough to pick that one value they intersect at (or have in common), then you'd be wrong when you say they are equivalent.
Number 4 makes the most sense because if both expressions are equivalent, then every value matches up. If not, then only one will. So having two values to substitute will most definitely answer the class question.
Hope this helps, let me know if I messed up! ;)
The formula of this equation would be
* 1.026^16 = 7,160.06
So from this equation we know that
Now we need to find the value of x, we need to multiply
* 1.026 16 times. Which will bring us to your answer. $
4,748.53
Answer:
5/2x, 5/2 y
Step-by-step explanation:
An enlargement means the scale factor must be greater than one
The only choice with a scale factor greater than one is 5/2x, 5/2 y
The answer: " x = 68, y = 72 " .
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Explanation:
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46 + (x - 3) + (y - 3) = 180 .
46 + 1(x - 3) + 1(y-3) = 180 .
46 + 1x - 3 + 1y - 3 = 180 .
46 - 3 - 3 + 1x + 1y = 180 .
40 + x + y = 180 ;
Subtract "40" from EACH SIDE of the equation:
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40 + x + y - 40 = 180 - 40 ;
to get:
x + y = 140 ;
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Now:
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65 = (x - 3) ;
↔ x - 3 = 65 ;
Add "3" to EACH SIDE of the equation;
x - 3 + 3 = 65 + 3 ;
to get:
x = 68 .
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Now:
Since: "x + y = 140" ;
Let us plug in our known value, "68" ; for "x" ;
to solve for "y" ;
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x + y = 140 ;
68 + y = 140 ;
↔ y + 68 = 140 ;
Subtract "68" from EACH SIDE of the equation; to isolate "y" on one side of the equation; and to solve for "y" ;
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y + 68 - 68 = 140 = 68 ;
y = 72 .
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So, solve for "x" and "y".
x = 68, y = 72 .
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<span>m∠CED = </span><span>1/2(m∠AOB + </span><span><span>m∠COD)</span> = 1/2(90° + 16°) = 1/2(106°) = 53°</span>
