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4 years ago

In hydrogen, the transition from level 2 to level 1 has a rest wavelength of 121.6 nm.

Physics

1 answer:

leonid [27]4 years ago

6 0

Answer:

according to the Bohr'smodel,

The change in wavelength, Δλ = λ₁ - λ₂ = λ₂ν/c

where λ are the respective wavelengths

ν = speed of the stars/objects =?

c = speed of light = 3 x 10⁸m/s

1. To find the speed for a star in which this line appears at wavelength 120.4 nm.

i.e λ₁ = 120.4nm and λ₂ = 121.6nm

ν = [(120.4nm - 121.6nm)/121.6nm] x 3 x 10⁸m/s

ν = -2.71x10⁶m/s

2. To find the speed for a star in which this line appears at wavelength 120.4 nm.

i.e λ₁ = 120.4nm and λ₂ = 121.6nm

ν = [(120.4nm - 121.6nm)/121.6nm] x 3 x 10⁸m/s

ν = -2.71x10⁶m/s

3. To find the speed for a star in which this line appears at wavelength 121.4 nm.

i.e λ₁ = 121.4nm and λ₂ = 121.6nm

ν = [(121.4nm - 121.6nm)/121.6nm] x 3 x 10⁸m/s

ν = -4.94x10⁵m/s

4. To find the speed for a star in which this line appears at wavelength 121.4 nm.

i.e λ₁ = 121.4nm and λ₂ = 121.6nm

ν = [(121.4nm - 121.6nm)/121.6nm] x 3 x 10⁸m/s

ν = -4.94x10⁵m/s

5. To find the speed for a star in which this line appears at wavelength 122.2 nm.

i.e λ₁ = 122.2nm and λ₂ = 121.6nm

ν = [(122.2nm - 121.6nm)/121.6nm] x 3 x 10⁸m/s

ν = 9.872x10⁵m/s

6. To find the speed for a star in which this line appears at wavelength 122.2 nm.

i.e λ₁ = 122.2nm and λ₂ = 121.6nm

ν = [(122.2nm - 121.6nm)/121.6nm] x 3 x 10⁸m/s

ν = 9.872x10⁵m/s

7. To find the speed for a star in which this line appears at wavelength 122.9 nm.

i.e λ₁ = 122.9nm and λ₂ = 121.6nm

ν = [(122.9nm - 121.6nm)/121.6nm] x 3 x 10⁸m/s

ν = 2.08x10⁵m/s

8. To find the speed for a star in which this line appears at wavelength 122.9 nm.

i.e λ₁ = 122.9nm and λ₂ = 121.6nm

ν = [(122.9nm - 121.6nm)/121.6nm] x 3 x 10⁸m/s

ν = 2.08x10⁵m/s

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V = √(F / μ)

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F(n) = n (v / 2L)

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μ = 0.00725 / 0.62

μ = 0.0116 ≅ 0.0117kg/m

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v = 592.69m/s

Second overtone n = 3 since it's the third harmonic

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F₃ = 3 * [592.69 / (2 * 0.62)

F₃ = 1778.07 / 1.24 = 1433.927Hz

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Since it's the first fundamental, n = 1

1433.93 = 344 / 4L

4L = 344 / 1433.93

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L = 0.0599

L = 0.06cm

L = 6cm

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